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fgrep to file plus some

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# 8  
Old 02-25-2009
could give a sample path to a file you're using:
Code:
fgrep"${getdate}"${PROCESSOR}${LOGINID}/Sum_SCR_Records.${YEAR}.log

is 'PROCESSOR' somehow "separated" from 'LOGINID' in your file path?
How would one derive the value of LOGINID?

how about:
Code:
sed "/${getdate}/ s/^/${LOGINID}/" ${PROCESSOR}${LOGINID}/Sum_SCR_Records.${YEAR}.log

# 9  
Old 02-25-2009
fgrep"${getdate}"${PROCESSOR}${LOGINID}/Sum_SCR_Records.${YEAR}.log

maybe this wil help

fgrep 02242009 /u/customer/ski/Sum_SCR_Records.2009.log

PROCESSOR is passed here from another script which is always the location of the directory.
LOGIN is coming from the file that is read in this particular script trying to get the data.
The logs do not contain the login but I need to add it to the output.

Sorry to be so confusing.
# 10  
Old 02-25-2009
try the posted 'sed'
# 11  
Old 02-25-2009
thank you , I'm working on it but I have a bad substitution going on. Do I still output to a new file because I do not want to replace what is in the original file.
# 12  
Old 02-25-2009
Quote:
Originally Posted by ski
thank you , I'm working on it but I have a bad substitution going on. Do I still output to a new file because I do not want to replace what is in the original file.
yes, redirect the output of 'sed' to a new file in the usual manner.
# 13  
Old 02-26-2009
Hi vgersh99,

I still need you. My problem is the date in the log file is formatted as such: 02/25/2009 so I think the sed command is confused. It says
sed: Unrecognized command: /02/25/2009/
Thanks,
Toni
# 14  
Old 02-26-2009
Code:
sed "/${getdate}/ s#^#${LOGINID}#" ${PROCESSOR}${LOGINID}/Sum_SCR_Records.${YEAR}.log
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