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how to fix this awk script?

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Top Forums Shell Programming and Scripting how to fix this awk script?
# 15  
Old 02-12-2009
Code:
awk  '/user|nas|group/{ for (i=1; i<=NF; i++) {
                   if ($i ~ /user/) printf $i FS 
                   if ($i ~ /nas|group/) a[i]=$i } 
                  for (j in a) printf a[j] FS
                  print "" ; split("",a) }' file

# 16  
Old 02-12-2009
Thanks for answering my question, I greatly appreciated! but the output is not 100% I want, see the last line, nas_m is on the last column. while i want all the nas show up on the second column.

user_a group_a nas_b
user_d nas_b group_b
user_a, group_c
user_c group_d nas_m


Quote:
Originally Posted by vgersh99
Code:
awk  '/user|nas|group/{ for (i=1; i<=NF; i++) {
                   if ($i ~ /user/) printf $i FS 
                   if ($i ~ /nas|group/) a[i]=$i } 
                  for (j in a) printf a[j] FS
                  print "" ; split("",a) }' file

# 17  
Old 02-12-2009
ok, I see what he's doing:
Code:
awk '/user|nas|group/{ for (i=1; i<=NF; i++) {
                   if ($i ~ /user/) printf $i FS
                   if ($i ~ /nas/) a[i]=$i
                   if ($i ~ /group/) b[i]=$i }
                  for (j in a) printf a[j] FS
                  for (j in b) printf b[j] FS
                  print "" ; split("",a); split("",b) }' file

# 18  
Old 02-12-2009
thank you thank you thank you! Smilie Smilie Smilie

This little script is awesome! Saved for future use.

Quote:
Originally Posted by vgersh99
ok, I see what he's doing:
Code:
awk '/user|nas|group/{ for (i=1; i<=NF; i++) {
                   if ($i ~ /user/) printf $i FS
                   if ($i ~ /nas/) a[i]=$i
                   if ($i ~ /group/) b[i]=$i }
                  for (j in a) printf a[j] FS
                  for (j in b) printf b[j] FS
                  print "" ; split("",a); split("",b) }' file
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