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If the user isn't present on the server, ssh won't login in the first place and no reset will happen. So if the statement executes at all, then they must exist.

The ' around && aren't optional....

Variables from your end don't go to the other end either, and don't get substituted before they're sent because you put them in single quotes.

Your program still makes no sense. Why would you...

Functions entered on localhost won't appear on the other host.

I have no idea what this '-a' option is and can't find it in any of my manual pages.

I have no idea what that shell statement is...

If you can do 'sudo bash' you have root permissions. The other user possesses a key file which allows him to do so. If your user doesn't have the same key, with the right file permissions on that...