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okay..

even the following might work:

awk '$0~pat {n=NR+5} NR!=n' pat='10000' $1 > $2
mv -i $2 $1


and running the above by:

sh script_name file_name tmp_file_name


Right ?

I was trying to do this to all files ending with .txt in my destination directory using the following code :

cd /my_destination_dir/

for i in `ls *.txt`
do
awk '$0 ~ pat {n=NR+5} NR!=n'...

I found a flaw in that 'awk' code..

lets say file as c.txt :

10000
a
b
c
d
e
..
10000
a
b
c
d
e
..
.
It works fine for the above file as the first set of data is that of same...

Thanks. it works cool.

isn't that possible with sed ?

Hi,

I'm trying to search for some number and from that line, i need to delete the 5th line exactly.

Eg:
Consider below as text file data:

10000
a
b
c
d
e
.
.
.
10000
w
q
t