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okay, so what I recommend when you have the time is to read the man page for 'sh' or 'bash' which will explain how 'for' works, as well as backticks, redirects, substitution, etc.

also read the...

Ok, I checked your image.

You are doing this:
find $directory -type f -perm 666 -print | wc -l > results.txt
which is outputting the result of 'wc' to 'results.txt' Thus results.txt contains...

echo $count will display the value of 'count' but not of 'COUNT'.

what does 'echo $COUNT' display, or are you just typing in haste?

can you post the script?

the find ..-exec flag is for operating on every find result. Think of batch renaming, archiving, or deleting.

COUNT=`wc -l results.txt|cut -f1 -d' '`

cuts the first space delimited field, which is your value

the invalid arg error seems like it would have been caused by mixing up the options and args (i.e. -user -u+6 rather than -perm -u+6)

the strange results could be caused by subdirectories. find...

find /path/to/$directory -user $username -perm -u+r,-u+w

this will give this list of files, i.e. you don't need a loop.