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Hi ,
In a directory list of ddl files are stored in the given format above. Above is the sample ddl file. The ddl file name is same as that of table name ie email_notifications.ddl
I want to...

Thanks for your reply. It should have been


unset counter
counter=15

Have made one more correction

date_from=$(date -d "$date_to +0 days" '+%Y%m%d')
to get file size for every 15 days of...

I have made some correction. Please let me know if there is a better way to do it.



unset date_to
unset date_from
unset counter=15
date_to=$(date -d 2018-06-15 +"%Y%m%d")
todate=$(date...

How to compare two input date string?

What I am basically trying to get here is get file names in a directory for a particular date range.
I would like to get the file data growth over a certain...

Hi,

Can we apply multi threading in Unix. I am using bash shell.
We have a generic script to load the data to table based on file input. For each file there is an individual table to load.
...

what is the significance of each attribute below in two lines

sed -e 's/.*\(201[8-9][0-9]\{4\}\).*/\1/g'
sed -e ':a' -e 'N' -e '$!ba' -e 's/\n/ /g'`




1st line - what I have understood...

Thanks!
I did not understand below
print "rm " FILENAME > "remove_old_files.sh"

for i in *w*.txt; do mv -v "$i" $(echo "$i" | tr 'w' 'd'); done
something like this?
and using sed to replace the content?

Please use CODE tags as required by forum rules!

We have around 1000 scripts in a specific folder like mcx001.txt, mcx002.txt, mcx999.txt, mce001.txt etc
We need to rename those files where 3rd character is "x" and should be replaced by "y".
So...

Many thanks!
One problem I am seeing here is that awk also is reading the comment lines.
Is there a way to ignore all comment lines at the very beginning? Should I need to create a separate post...

Hi,
I want to pull all the files that have the pattern like the input file given. In a directory there are say 5000 files out of which 1000 files have the text starting with 'submit file'.
and from...

I am running the program as a .sh script.


#!/bin/ksh
awk ' NR==1 {
print "File | Jobname | node | pfile | metafile | tname | priority |...

when I replaced *.sh by the line in your original code

I am getting below error:

awk: cmd. line:37: fatal: can not open file 'awk' for reading ( no such file or directory )

Hi,

It does not work when I replaced the *.sh by
awk '/^submit/{print FILENAME;nextfile}' *.sh
in the orginal solution you provided. It gives error can not open file awk

Thanks Guys for the help.
Is there a way to use awk '/^submit/{print FILENAME;nextfile}' *.sh instead of *.sh with awk in the script above.
There can be different files with different pattern and...

In a particular directory, there can be 1000 files like below.

filename is job901.ksh
#!/bin/ksh
cront -x << EOJ
submit file=$PRODPATH/scripts/genReport.sh maxdelay=30
&node=xnode01
...

Can the output have all filenames, even if nothing found with awk

Can it be done using grep? thanks

There can be thousand of .ksh in a specific directory where sql files are called from ksh.

Requirement is to loop through all the files content and generate a report like below:

Jobname ...

Hi
I am comparing two files with comm -13 < (sort acc11.txt) < (sort acc12.txt) > output.txt
purpose: Get non matching records which are in acc12 but not in acc11...
TI am getting WRONG output....

#!/usr/bin/ksh
cat /home/test/mail
export email=`cat /home/test/mails`
mailx -s "test---" ${email}
I am getting not found error

cat mails
amit@gmail.com
if i write below ,its working fine
...

var=abc_cde_def_ghi_678.txt

Expected output:
cde_def_ghi_678.txt

Is there a better way to achive this other than cut command?
Basically, I need to remove the 1st word and _ from the string.
...

Thanks for your reply. Can not we use regular expression something like [fFnN] ?

PATTERN_SEARCH_LIST="FN201_X_*_"$file_date"*.txt"
for file_name in $PATTERN_SEARCH_LIST
do
print "file name:"$file_name
#add process logic here
done

How to...

Thanks for the reply. I have not tested the code yet but when I tried below piece of code

VAR=COL2 VAL=1 sed -i "s/^${VAR}=.*/${VAR}=${VAL}/" test.txt>tmp
mv tmp test.txt
The last line is not...