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post# 10 will work.

Not very sure but looks like $bootpathf has "/" in it's value as it is a path.
e.g. abc/def/ghi
If so, use following:

sed -i "s#BOOTPATH#$bootpathf#g" $rootfspath.xml


Replace / in sed...

sed 's/\(.\)dwh/\1\
dwh/g' inputFile

To avoid having 1st line as new line.

awk -F'[:,]' 'NR==FNR{key[$2]=$1;next}{print $1,$2,$3," "key[$3]}' OFS=, file2 file1 >outputfile

You might be using single quotes. Make sure you use double quotes.

sed -i "s/BOOTPATH/$bootpathf/g" file.xml

If no good, post your command.

If you only want to replace 1st field to 1,

sed '/\([0-9]*\)/1/' data
OR (if 1st field has only one length data)

sed '/\(.\)/1/' data
OR

sed '/\([^ ]*\)/1/' data

* can be removed if 1st...

awk '/------------/{nr=NR;next} NR==nr+2' inputFile

paste File1.txt File2.txt File3.txt File4.txt

works for me. You may try:

paste -d'\t' File1.txt File2.txt File3.txt File4.txt

Pls provide an expected output for above input.

awk 'NR==FNR{a[$1]++;next}{if(!a[$1]) print $0}' data_1 data_2

Your current output and desired output look same.
Also you didn't mention the inputs completely. Pls mention sample of each file content, expected out, current output, the command you are tried.

#!/bin/ksh
echo "Enter the search patterh: "
read a
grep "$a" *.rep

always post exact input (or most generalized one). Try following:
echo "**abcd **1234** efgh**" | sed "s/\*\*/'''/2;s/\*\*/'''/2"OR
echo "**abcd **1234** efgh**" | sed...

echo "abcd **1234** efgh" | sed "s/*/'/g"

awk '$12 != 0.0015' inputFile

try:
export output=$(crontab -l | grep GBOUAT8 | grep UTP | grep -i stop | sed 's/\\//')

Yes, Bottom up is not needed. Thanks.

ab=$(echo $dirk | awk '{for(i=1;i<=NF;i++) if(index($i,"ab")){print $i;exit;}}')

awk -F'[/"]' '{print $5,$7}' inputFile

#!/bin/ksh
i=1
while [ i -le 10000 ]; do
touch file$i
i=$(expr $i + 1)
done

Execute script as:
a.sh 20110114 "b c d"And pass 2nd argument in quotes to sql proc:
<sql_proc> "$2"
But not very sure about sql procedure. If above doesn't work, then you may do following:...

As you can see above, In my script output,
a.sh 20110114 'b c d'
arguments count ($#) is 2
1st argument ($1) is 2011011
2nd aguument($2) is b c d

If you are passing your argument to some other...

bottom up way:
sed '311,592 d;105,107 d;53,59 d;10,51 d' infile > outfile

Thanks Chubler_XL. It should be:
date '+%d/%b/%Y:%H' | awk -F: '{printf("%s:%02d\n",$1,$2>=4?$2-4:24-(4-$2))}'

#!/bin/sh
echo $#
echo $1
echo $2
echo $3
When I run it as:
a.sh 20110114 'b c d'
I get following:
2
20110114
b c d


Please mention what exactly you are doing.
Probably code snippet,...