Search Results

why not use 'sort'?

'sort -r inputfile'

#!/bin/sh

arr=(1 2 3 4)

len=${#arr[@]}

for(( i=1; i < $len; i++))
do
if [ ${arr[$i]} -eq 2 ] ; then
echo "exec some statement"
fi
done


.Aaron

i think may be use
set qu=($(condor_q|tail -1))

i test the statement in bash:
$ ls
a.sh hsperfdata_root https-admserv-9d93b4d6

$ arr=( $(ls))
$ echo ${#arr[@]}
3...

u can try this:

lame $src $dst && rm -frv $src || echo "$src encoding failed"

when lame $src $dst return zero if lame encoding sucess.

len= size of array
for i in $len
do
#Create a destination directory
ssh -q ${store_username[$d]}@${store_host_name[$c]} mkdir temp
#scp files to host
scp -r /root/temp...

Output=""
for(( i = 0; i< ${#HBA_WWN[@]}; i++))
do
Output=$Output"HBA at ${HBA_WWN[$i]} is ${HBA_STA[$i]} ;;"
done
echo $Output


.Aaron

$ cat file1
Switch not possible Error code 1234
Process number 678

Log not available Error code 567
Process number 874

Log not available Error code 333
Process number 34

Log not...

read str < <(cat file1 | tr "\n" " ")
echo $str


cat file1 | tr "\n" " " replace the "\n" to space,

read str < <(cmd) read the cmd 's stdout in the string str

arr[$0]++, and if($0 in arr)
u maybe use this:
arr[$NF]++ and if($NR in arr)

The last one parameter of `ls -l ` is file name.

$0 has much info about every file in linux.

According to your description above. I write down a script as follow.
Wish to help you!

Assume there is a space between [Date: and 2008-05-16]
>cat infile
unixytreqasadddd <unix_unix@unix.com>...

using awk (linux + bash):

awk ' BEGIN {RS = ""; FS = "(\n)| ( )"} # set the record separator as ""

# save the first file name and 4th field of it in an array
NR == FNR { ...

you can use the "rsync" to backup your files, if there is the tool in your system.

e.g.
rsync source/*.c dest/

more detail in man rsync

regards
.Aaron

try this code:

#! /bin/bash'

i=0;

for file in `ls`
do
let i++
awk '{
if( $0 !~[:space:]?$/)
suffix = " '" $i "'"
else
...

dirname or substring removal operator ${%}

str="/home/psv/file/test.ksh"

echo `dirname $str`/
echo "${str%/*}/"

assume that there is only a single line in fileB!
using awk :

awk 'NR == FNR {var=$0}
NR != FNR {
if(FNR > 1) $3 = "+"$3;
print $3 "*" var
}' FS="(+)|(-)"...

if you want to do this job with script, you can try code as follow:

#!/bin/bash

INFILE=output.txt

#replace the double quote with space
LIST=$(sed -e 's/\"/ /g' $INFILE)

zip archive.zip...

awk 'BEGIN{FS="( )|(,)"} /^Name/{n=$NF}/^Address/{split($0, arr, "\""); a=$2" \"" arr[2]"\""}/^City/{print n,a,$NF}' data
maybe, This is what you want!

.Aaron

FS means Field Separator , using FS="( )|(,)" means current FS is the space or ','
if you use the statement, the result is
lastname1 111 Hilversum
lastname2 222 Bussum
lastname3 333 Amsterdam
...

>cat x.txt
z 11 az
x 12 ax
y 13 ay
>cat y.txt
ay TT
ax NN
>sort x.txt > sx.tmp && sort y.txt > sy.tmp && join -1 3 -2 1 -o "1.1 1.2 1.3 2.2" sx.tmp sy.tmp | sort -r && rm -fr *.tmp
y 13 ay TT...

oh，sorry, I forgot the "max =cur", when I input my code into the reply!

.Aaron

try this code:
#!/bin/bash

#constant
INFILE="max.txt"

#core script
awk ' BEGIN { OFS=FS=":"; cur=max=0; seen=""}
{
cur = length($1)
if(cur > max ){
...

try this code(bash):

#!/bin/bash

#constants
CNT=10
SOURCE="file1.txt"
RESULT="file2.txt"

#copy first field to file2.txt from file1.txt
cat $SOURCE > $RESULT
printf "\n" > $RESULT
...

try this:

case ${FileName##*.} in
txt|dat|csv)
mv $SourceFileDir/$FileName $TargetFileDir/ ;;
esac

(Bash)