compaision of dates


 
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# 1  
Old 06-22-2007
compaision of dates

how can compare dates
example :
date1=23:06:2007;
date2=22:06:2007;
how can compare these two
thank u,
sree
# 2  
Old 06-22-2007
20070623 - 20070622
# 3  
Old 06-22-2007
Code:
mDate1='23:06:2007'
mDateA=`echo $mDate1 | sed 's/\(..\):\(..\):\(....\)/\3\2\1/'`
mDate2='22:06:2007'
mDateB=`echo $mDate2 | sed 's/\(..\):\(..\):\(....\)/\3\2\1/'`
if [ ${mDateA} -gt ${mDateB} ]; then
  ...
else
  ...
fi

gt: Greater than
ge: Greater or equal
lt: Less than
le: Less or equal
eq: Equal
# 4  
Old 06-22-2007
Since this is a C forum, one way using C to compare dates using libc:

Code:
#include <time.h>
/****************************
date_compar ()
parameters:
       date1 and date2 - dates to compare
       fmt - format (see man date) of the date string
       full_day - (because date + time causes intermediate value)
               0 == include seconds in differences 
               1 == do not include seconds, only compare days
returns:
     0- parameters are equal
     1- date1 is more recent
  (-1)- date2 is more recent
  
     assumes dates are valid
*********************************/
int date_compar(const char *date1, 
                const char *date2, 
                const char *fmt, 
                const int full_day)
{
	struct tm tmp;
	time_t one=0;
	time_t two=0;
	int retval=0;
	
	strptime(date1, fmt, &tmp);
	one=mktime(&tmp);
	strptime(date2, fmt, &tmp);
	two=mktime(&tmp);
	if( full_day==1)
	{
		one/=86400; /* convert seconds to days */
		two/=86400;
	}
    if (one > two)
    	retval =1;
    if(two > one)
    	retval=(-1);
    return retval;			
}

int main()
{
	char *date1="17:06:2007";
	char *date2="18:06:2007";
	char *fmt="%d:%m:%Y";
	int result=date_compar(date1, date2, fmt, 0);
	char chresult=' ';
	
	chresult=(result==0)? '=': (result > 0)? '>': '<';
	printf("%s %c %s\n", date1, chresult, date2);
	return 0;
}

The other way is to use a Julian Day algorithm (like ACM 199) to convert a Gregorian date to a JD, then compare JD values.
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