Extract part of an archive to a different file


 
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Old 09-10-2015
You don't need random access for your output file. You'll just be doing sequential writes to your output file. You'll also just doing sequential reads from your input file (once you seek to the proper starting position).
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AR(1)							      General Commands Manual							     AR(1)

NAME
ar, aal - archivers SYNOPSIS
ar [dmpqrtx][abciluv] [posname] archive [file ...] aal [dpqrtx][clv] archive [file ...] EXAMPLES
ar r libc.a sort.s # Replace sort.s in libc.a ar rb a.s libc.a b.s # Insert b.s before a.s in libc.a DESCRIPTION
Ar allows groups of files to be put together into a single archive. It is normally used for libraries of compiled procedures. Aal is like ar, but is to be used with the ACK compiler. The following keys are allowed: d: Delete. Ar will delete the named members. m: Move named files. Ar expects a, b, or i to be specified. p: Print the named files (list them on stdout) q: Quickly append to the end of the archive file. r: Replace (append when not in archive). t: Print the archive's table of contents. x: Extract The keys may optionally concatencated with one or more of the following: a: After posname b: Before posname c: Create (suppresses creation message) i: Before posname l: Local temporary file for work instead of /tmp/ar.$$$$$ u: Replace only if dated later than member in archive v: Verbose SEE ALSO
anm(1), asize(1), nm(1), size(1). AR(1)