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grepping a range of values

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# 1  
Old 05-07-2012
grepping a range of values
I need to return all records in a file starting with

a row that says

Code:
TABLE: <tabl name>
lists of hexadecimal records

TABLE: <some table>

TABLe is a key word in the file. I know the name of the table I want to start with. I do not know the name of the table that I will end with. I just need to end when the word: TABLE: comes up.

I need everything between those 2 records. This field has 1 column.
Last edited by Scrutinizer; 05-07-2012 at 02:10 PM.. Reason: code tags
# 2  
Old 05-07-2012
Hi, try:
Code:
awk 'p && /TABLE/{p=0}p;/TABLE: <tabl name>/{p=1}' infile

# 3  
Old 05-07-2012
Or you can do it this way...
Code:
ex -s +'/tabl name/;/TABLE:/p | q!' file

# 4  
Old 05-07-2012
If it is including the TABLE lines, then:
Code:
sed '/TABLE: <tabl name>/,/TABLE/!d' file

# 5  
Old 05-07-2012
Quote:
Originally Posted by Scrutinizer
If it is including the TABLE lines...
Good point i didnt realize that the op wanted to exclude them...so here is my take w/o the TABLE lines...
Code:
ex -s +'/tabl name/+1;/TABLE:/-1 p | q!' file

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