Programming

Hello All,

I am having this issue...where I am actually having hard time understanding the problem:

The code is as follows:

Am getting warning at line " *var[j] = "name" ": deprecated conversion from string constant to 'char*''

I know am doing something wrong......bt. can't seem to figure out what!

Thanks n Regards,

This is a C++ warning about using C, and you will get a lot of them if you will write in a such manner. Don't mix C and C++ styles, idioms and constructs. Either use <stdio.h>, malloc, printf, char*, etc. (so C) or use string, cout, iostream, new, etc. (C++).

===

Ok, I was wrong. But it's a bad style anyway, IMO.

Giving same warning even if I change to total C++ style or vice versa!

yazu: It's nothing to do with using C++ versus C calls. It's perfectly valid to use malloc and cout and new together -- the tricky bit comes figuring out when to call free() and when to call delete().

The error means exactly what it says: It's complaining about a conversion from const char * to char *.

What's the only const char * you have? "name".

So:

Code:

#include<iostream.h>
 
void fxn(char*** var)
{
int i =4;
*var = (char**)malloc(i*sizeof(char*));
for(int j =0; j<4; j++)
{
*var[j] = (char *)"name";
cout<<*var[j];
}
}
 
int main()
{
 
char** var;fxn(&var);
 
}

Just be careful not to free() or try to modify "name" later.

@Corona688

If I typecast constant string "name" to (char*)"name"....it gives me "Segmentation Fault"!!!!

It's getting the order of operations mixed up, adding an offset to a pointer then dereferencing it instead of dereferencing it then adding an offset. (*var)[j] instead of *var[j]

@Corona688

Thank you ....even when I added bracket so that it dereferences properly ...got perfect answer!!!!!!
Thanks ton

---------- Post updated at 11:38 AM ---------- Previous update was at 11:36 AM ----------

@yazu:
Thanks ....will surely try to implement good styling