[C language] system function print output when not expected.


 
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Old 05-04-2010
[C language] system function print output when not expected.

Hi,

I am new to C and have a little problem.
I am not planning to be a C expert, but this would be nice to understand.

The problem is that a 'system' call prints it output to stdout, when I do not expect this.

This is the program:

trial.c

Code:
#include <ctype.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>


int main() {

fprintf(stdout, "-> main()\n");

int return_value;
char passing_var[9];

strcpy(passing_var, "datum");

fprintf(stdout, "main() passing_var  = %s\n",passing_var);

return_value=date(passing_var);

fprintf(stdout, "main() return_value = %s\n",return_value);
fprintf(stdout, "<- main()\n");

}


int date(char *passing_var) {

fprintf(stdout, "-> date()\n");
fprintf(stdout, "date() passing_var  = %s\n",passing_var);

char command[128];
int date_return;

strcpy(command, "date");

fprintf(stdout, "date() command      = %s\n",command);

date_return=system(command);

fprintf(stdout, "date() date_return  = %s\n",date_return);
fprintf(stdout, "<- date()\n");

return date_return;

}

This is the output:

# ./trial

Code:
-> main()
main() passing_var  = datum
-> date()
date() passing_var  = datum
date() command      = date
Tue May  4 13:53:42 GMT 2010
date() date_return  =
<- date()
main() return_value =
<- main()

I do not understand why the 'date' output is printed in the 'date()' subroutine and not given to the 'date_value' variable.

Probably wrong declarations and other mistakes.

Can someone help and shine a light on this ?

Many thanks in advance,

E.J.
 
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