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Hello anshu ranjan,

Could you please try following and let me know if this helps.

awk '{sub(/\/[^|]*/,"");print}' Input_file
Thanks,
R. Singh

Hello anshu ranjan,

Could you please try following.

sed "s/^/'/g;s/$/';/g" Input_file
Output will be as follows.

'Member Analytics Engine';
'Enterprise Manager';
'Dev Tutorial';
...

As date arithmetics are not that easily done, and my mawk doesn't support dates at all, I'll propose a shell script for you:NOW=$(date +%s)
D15=$((86400*15))
while IFS="=" read A B; do [ "$A" ==...

Please use code tags, not icode tags!

The effect that bothers you is one of the drawbacks of the for construct, as it can't tell spaces embedded in lines/variables from item separators. Two while...

#!/bin/ksh
while read user
do
while read proj nm
do
echo "Delete user profile \"${user}\" FROM ${proj} ${nm}"
done < file2
done <file1 > OP1

Ignore this..I haven't seen the...

Hello Anshu,

You can try following and let me know if this helps you.

while read line1; do while read line2; do echo "Delete User Profile \"$line1\" FROM $line2"; done < "file2"; done < "file1"...

Hello Anshu Rajan,

Kindly use code tags for commands/inputs/codes used in your posts in spite of HTML codes. Could you please try following and let me know if that helps.

awk -F"|" -vvar=5...

I suggest to read the man page of sed, especially the part about "one-address-commands".

I hope this helps.

bakunin

In recent shells, tryfor (( i=1; i<=16; i++ )); do echo $DATE >> file1; done

@Akshay, only the second option wil work if any of the names contain spaces, and only if "$filesystems/$project" is in double quotes..

Try :

for i in $(cat filesystems_file); do

for j in $(cat project_file); do
echo du -h $i/$j
done
done

OR

while read filesystems; do
...

Delete the continue

awk '{print $1 " &&echo \"scp done\" >> out.txt"}' file1 > file2

You certainly don't need to build shell scripts inside awk to do that.

while read LINE
do
"$LINE" && echo "$LINE: scp done"
done < file1 > out.txt

$ awk -F/ '{print "/"$2"/"$3"/"$4"/config"}' infile
/java/usr/abc/config
/java/usr/xyz/config
/java/usr/ab12/config


---------- Post updated at 05:21 PM ---------- Previous update was at 05:16...

paste -d" " file1 file2

To find whether a file has a CR or not you can use grep, this should print the lines with a CR:

grep '^M' file1Type <Ctr-v><Ctr-m> to get ^M and not a ^ and an M.

Regards

^M is a carriage return.

You should understand a few things first:

CR = \r = Carriage Return
LF = \n = Line Feed

In DOS, all lines end with a CR/LF combination or \r\n.
In UNIX, all lines...