Search Results

OBTW, I looked further into this; and the WP theme appears to be a custom theme written by the website owner (infobeans), because the theme name is also "infobeans" and this does not appear to be a...

You don't really need an app to tell you the CMS (for this site, anyway).

If you look at the HTML source code, you will see it is a Wordpress site, for exampleL


<script...

Using: CMS detection

What CMS Is This? (http://whatcmsisthis.com/)

it seems like the CMS is Wordpress (although other detectors don't see that)

Using:

WordPress Theme Detector...

Go through

https://iosscripts.com/

its jQuery Plugins

This looks like homework to me, but I'll give you a start. Bit inversion is usually taken to mean reversing the order of bits, BTW. "flip" means change from 1->0 or 0->1.

Use a bit field to...

awk '$2 ~ /DMX/' input.txt > output.txt

Reversing the sort.

Set a variable called TEMP to the value of the variable PATH_PROC_USER if PATH_PROC_USER has a value. If PATH_PROC_USER does not have a value (is null), set Temp to a null string (the ""). Which is...

To my knowledge there is no equivalent of a set -x for an awk programme. I usually add printf() statements at key points and print the information I am interested in seeing.

EDIT: @Corona688, ...

Two issues: To stop read from interpreting the line using read and losing beginning and ending tabs you can use:
while IFS= read -r FXML_line
to not lose those tabs during variable expansion use ...

Well that is what I mean, 07 produces 7 digit wide numbers with 0-padding, so 23 becomes 0000023

Try: printf "%07d"

I am guessing your shell does not support this. You would need bash or ksh93.

Try putting double quotes around the back ticks...

-or alternatively make use of grep's return code, perhaps this will also server your purpose-
if grep -Fq "${TARGET_PATH_OK}"...

Or remove the outer brackets..

Hi try

if [[ -n `grep ${TARGET_PATH_OK} ${PREPAVAL_TRAVAIL}/${EDI_DIRS_list}` ]] && [[ -d `grep ${TARGET_PATH_OK} ${PREPAVAL_TRAVAIL}/${EDI_DIRS_list}` ]]

There should be no spaces between the...

@mayursinguru
Contains the same error - using an integer compare -eq when it needs a string compare = and the values on both sides of the compare encased with double quotes.

nom_PDF=substr($3,2,length($3))

awk -F\;
'{
nom_PDF=$3;
svar=$0;
gsub(/[ \t]+$/,"",svar)
printf("%s%-56s;\n",svar,name_PDF);
}' one_text_file > second_text_file

Answer for your questions

${string##substring} Deletes longest match of $substring from front of $string

${string%%substring} Deletes longest match of $substring from back of $string.

...

you tried like below ?


$ cat one.sh
#!/bin/sh -vx
a()
{
echo "ABCD"
return 0
}
a
echo "Finished"

$ ./one.sh
#!/bin/sh -vx
a()
{
echo "ABCD"
...

This is how it works:

#! /bin/bash
functB () {
echo "Im in functB"
}

functA () {
echo "Im in functA. Going to functB"
functB
echo "Im back in functA"
}
...

$ i=1
$ i=`print "%06d" $i`
$ echo $i
000001

See if this works for you:
printf "%06d" $i

You also need a space before the square bracket.

Actually if your shell supports string operations, you might find this simpler and save a cpl of processes...