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You may want to try
awk '
1 == match ($0, "[^ ]") {ORG = $0
}
{IX = index ($0, " ")
...

Building on what you had come up with, try:
awk -F'[^ ]' '
{ current_len = length($1)
last_len = length(last_line)
len = current_len > last_len ? last_len : current_len
last_line =...

try:
awk -F";" '
NR==FNR {a[$4$5]=$0; f6[$4$5]=$6; next}
a[$4$5] {$6=f6[$4$5];}
1
' OFS=";" file1 file2

Try this:-

sed 's/,//g;s/Bytes//g;s/GB//g;s/ //g' input_file | awk -F";" '
BEGIN {
s1=0;
s2=0;
s3=0;
s4=0;
} !/Parent/ {
s1+=$9;
s2+=$10;
...

Yes, you are right, but exponentiation is even more CPU intensive than multiplication.

It will work with slight corections:awk -F ";" -v OFS=";" '
function GSUB( F ) {gsub(/\./,",",$F)}
GSUB( 6 )
GSUB( 7 )
GSUB( 8 )
1
' If you wanted the OFS to...

Like this?
awk -F\; '{t=$9;gsub(/,/,"",t);$9=$9 " (" (t/1024/1024/1024) " GB)"}1' CONVFMT='%.6f' OFS=\; file

awk -F\; '{gsub(/,/,"",$9);$9=($9/1024/1024/1024) " GB"}1' CONVFMT='%.6f' OFS=\; file

First remove all the strings and , from the $9.

use

awk -F ";" '{ gsub("[A-z]","",$9);gsub(",","",$9); print $9/(1024*1024*1024)}' file

Or to remove multibyte characters, you could try:
LANG=C tr -d '[\200-\377]' < infile

Can you paste the output of head -1 file1 | od -c for us so we can see the exact byte codes you have in this file.

In principle not too difficult:$ sed 's/^´╗┐//' file1, but you should be aware that these character graphics chars usually belong to a multibyte character set like utf-8 or so which may impose...

awk -F"\"" '/^share/{n=split($NF,a,"=");print "\\"a[n]"\\"$2","$4}' filename

This makes some assumptions about the input (like netbios= always being the last on the line), but might work:


awk -F '"' '
/share/ {
n = split( $0, a, "=" );
printf(...

You may notice that my code was formatted differently (the new lines matter).
If you want to write it on a single line, you'll need to use a semi-colon:

_0 = tolower($0); if (NR == FNR) A[_0];...