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Hello becal123456,

IMHO problem in your code is that you haven't done any increment on very first occurrence of a[$2 FS $4 FS $5 FS $6 FS $7] and when it goes into condition check happens first...

Thank you :)

For your questions, why a[$1] didn't throw errors because if any variable is NOT initialized in awk and we are using it in any condition or etc then its value will be considered as...

Try also
awk -F\| '
{LN[NR] = $0
L = length($3)
if (L>MX[$2]) {MX[$2] = L
D3[$2] = $3
}
}
END {for...

Hello beca123456,

Could you please try following.


awk 'BEGIN{FS=OFS="|"} FNR==NR{b[$1]=length($3)>a[$1]?$3:b[$1];a[$1]=length($3)>a[$1]?length($3):a[$1];next} length($3)<a[$1]{$3=b[$1]} 1' ...

You are overwriting the respective array elements with every occurrence of the respective customer. Try
awk -F"\t" '
NR == 1 {next
}

$2 ~ /grpA/ {a[$5] = a[$5]...

The regular expression search ~ is different from the string search via index.
You'll see differences e.g. with the following input files
A|123|qwer
A|456|tyui
A|45|wsxe
B|789|dfghA|123|qwer...

The following variant does a precise lookup (to supress duplicates),
and does not need an array of delimiters:
awk '
BEGIN {
FS=OFS="|"
dl=";"
}
function strjoin(i, j){
if (i=="")...

Do yourself a favour and start indenting / structuring your code for readability and understandability. Try

awk -F\| '
{if (!(a[$1] ~ $2)) a[$1] = a[$1] DL[$1] $2
if (!(b[$1] ~...

Try "@val_num_desc"

You are using gawk so it was quite safe to assume it provides delete. Other awk versions don't necessarily, use split ("", ARR) then to clear array ARR.
awk and other (not all!) languages use...

For my convenience, I rearranged / -idented your code, and added the delete count statement:
awk -F"|" -vOFS="\t" '

{a = split ($2, b, ",")
for (i=1; i<=a; i++) if...

Maybe something more like:
gawk '
{ VAR=0
split($2,b,",")
for(i in b)
if(!(b[i] in s)) {
VAR++
s[b[i]]
}
print $1 "\t" VAR
for(i in s)
delete s[i]
}' input.tab
I don't...

You might want to consider an alternative approach. No sprintf() calls, no for loops to gather your keys, and no long lists of explicitly copied arguments; just a single substr() call. And, it...

!(DIG[1]) is a boolean expression that assumes the values 0 or 1 depending on that array element having a value or not. Actually above it is a - sometimes dicussed - shortcut for if (DIG[1] == 0)...

Sorry, I missed that in your request.

awk '
{
for(i=1;i<=length($0);i++){
ch = substr($0, i, 1)
if(ch ~ /[0-9]/){
d = ""
while(ch ~ /[0-9]/){
...

Different approach:awk '
{printf "%s", $0
gsub (/[^A-Za-z0-9]/, "")
n = split ($0, DIG, "[A-Za-z]*")
m = split ($0, CHR, "[0-9]*")
S = CHR[1]
...

Here is an alternative approach that will work with any standards-conforming version of awk. (Note that the standards say the behavior is unspecified if FS (or the ERE used in split()) is an empty...

A small variation, using reverse field separators, without sprintf and without FS="" :

awk '{n=split($2,O,/[^+-]+/); split($2,F,/[+-]/); $2=0; for(i=1; i<n; i++) $2+=(O[i+1] 1)*F[i]}1' FS=\|...

This is a nice approach, and works fine with gawk and other awk implementations that use FS="" to split each input character into a field. A similar approach that doesn't depend on this behavior...

Different approach, not sure if better/faster:awk '
{n = split ($2, T, "[+-]")
gsub (/[0-9]*/, _, $2)
split ($2, S, "")
for (t in T) $2 = $2 + sprintf ("%f",...

I am having trouble following the logic of your script.

The diagnostic you are getting is because the sequence x(i) is a request to call the function named x with the parameter i, you haven't...

You aren't far off. Using your indentation style and making a few minor changes:
gawk '
BEGIN{FS=OFS=" "}
NR==FNR{
brand[$1]=$2;
line[$1]=$0;
next
}
{
match($0,...

What Don is telling you is (and this, btw., has nothing to do with the system being a cluster or not - it is simply the behavior of every shell i know of, including bash):

The PATH variable is a...

Without telling us what the shared directory is (or the shared directories are), without telling us what program names exist in those shared directory or directories, and with the only sample program...

You can't tell the cluster to do that, but you can modify your .bashrc file on that cluster by resetting PATH after you source the shared initialization file:
source /home/shared/bashrc...