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Another variation:
for i in *.test; do
read new || break
mv "$i" "${i%%-*}-${new}.${i##*.}"
done <names.txt

Try also
ls *.test | while read FN && read NFN <&3; do echo mv $FN ${FN%-*}-$NFN.${FN#*.}; done 3<names.txt
mv 01-oldname.test 01-name1.test
mv 02-someoldname.test 02-name2.test
mv...

One approach is to load names into an indexed array and then use another loop to rename the files using the array:-
#!/bin/ksh

# Load names into an indexed array
c=1
while read file
do
...

That is correct, in the awk script this line: !/^#/ will only print lines that don't begin with a hash (#) character.

The same applies to the bash script implemented by this line [#]*) ;;

OK this here is awk for the new output:

gawk -v ADD_DAYS=300 '
/#(DATEA|SETTINGSBEGIN) / { print $2 }
/#VALUE TITLE/ { printf "%s\n\n", gensub(/.*"([^"]+)"/, "\\1","g") }
!/^#/' settings.txt
...

OK sorry for the misunderstanding.

Here is a GNU awk solution:

gawk -v ADD_DAYS=300 '
/#DATEA/ {
DT = mktime(gensub(/-/, " ", "g", $2) " 0 0 0")
DT += 24*60*60*ADD_DAYS
printf...

You could try this in bash script, it does require GNU date for the date calculations:

#!/bin/bash
ADD_DAYS=300
while read line
do
[[ "$line" = [#]DATEA\ * ]] && DB=$(date -d...

You could use GNU awk like this:

gawk -v ADD_DAYS=300 '
/#DATEA/ {
DT = mktime(gensub(/-/, " ", "g", $2) " 0 0 0")
DT += 24*60*60*ADD_DAYS
}
/#TEXT/ {
print strftime("#DATEB...

Unfortunately, 0.0.0.0 has different meanings depending on where it's used. The formal definition is given in RFC1122 Section 3.1.2.3, i.e this host on this network. Specifically, all available IP...

The culprit may be a "black hole" firewall response, which instead of refusing connection just stonewalls it by ignoring the attempt.

Hi.

Using bash operator "=~" with extended regular expressions:
#!/usr/bin/env bash

# @(#) s2 Demonstrate extended regular expressions, bash =~.

# Utility functions: print-as-echo,...

Perhaps, but your output file specification was precise. I think Chubler_XL got it right, no?

Another way of writing it would be:
sed 's/^([^)]*)-//' file

Note that the thing different from...

How about:
$ cat usertail
TMP=~/tmp.$$
REM="ok some"
echo "(ok)-test
(ok)-test-(ing)
(some)-test-(ing)-test
test-(ing)" > $TMP

for rem in $REM
do sed s,\($rem\),,g -i $TMP
done
sed...

maybe this will work too?

awk '/^\(/ {sub(/\(/,"");sub(/\)/,"")}1' infile

How about:

sed 's/^[(][^)]*[)]-//'

All the previous examples do not compare with a constant expression.
The following does:

if [[ $string_to_report == *" "?* ]]
then
echo "has 3 spaces followed by at least one more...

The updated spec is still ambiguous. The phrase: "ignoring three spaces at the end of the string" can be interpreted several ways. Any of them can be handled using standard variable expansions or...

@jim: my bash man page talks of =~ within [[ ]]
And the ERE must be unquoted...

Hmm. Do you mean something like:

[ ' f f'~='[ ]{3}' ] && echo hi

This purposely does not directly answer your question, but shows what I think you mean.
By ignore - does that mean spaces at...

Try TMP="${string% }"
[ "${TMP}" = "${TMP/ /}" ] && echo TRUE || echo FALSE

Your question doesn't make any sense.
If statements don't read data from pipes.
You have shown us four echo statements (each of which prints at least three consecutive spaces piped into if...

Yes. Use his awk solution. Most sed versions do not support ERE - what you want. awk does support it. I'm reasonably sure no other sed solution that is a single command and can be generalized...

How about something simpler replace all _ with - This gives the result you want:

echo "--_----__-___-_-__-" | sed -e 's/_/-/g'

Try removing the pipe (|) symbols from your sed expression.

Also, if the goal is to have just a line of dashes, you could just globally replace the underscore character.


echo...

Standard sed cannot do it like that, you could use 3 separate passes, but it is not the same:
sed 's/_-/-/g; s/-_/-/g; s/--/-/g' file
But that would not give the same result, since it would also...