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Some awk do not have {n,m} in their ERE, but all have index():
awk '(/^0[67][MV]/ && index($0,"003529")==26) {c=6} (c && c--)' file

Hi.

Here are some alternatives for versions of grep that do not support options -A and -B:
Print lines above, below pattern-matched line (context, window); "only" string matching pattern

...

Try also
grep -A5 "^0[67][MV].\{22\}003529" file

OR

awk '/^0[67][MV]......................003529/ {L = NR + 6} NR < L' file

I missed something: \1 is certainly a backreference to the ( ) and should become $1 in perl, and needs to be separated from the following text
perl -i.Original -pe '/^4000/ and s/(.{136})...

Hi,

What we forgot to mention in the other thread (https://www.unix.com/shell-programming-and-scripting/271787-search-replace-specific-positions-specific-lines.html) is that when you use 000...

You can easily port it to perl
perl -i.Original -pe '/^4000/ and s/(.{136}) 36|000/\1036/' file

/.../ is a regular expression; c.f. man awk: "Regular expressions are enclosed in slashes". A single / is pointless.
^ anchors the regex at begin-of-line (or string).
.* represents "any...

How about
id | awk '{gsub (/^.*=|\)/, "", $1); sub (/\(/, " ", $1); print $1}'
1000 userid

Hi, try:
sed '/^4000/s/\(.\{136\}\).../\1036/' file
or
sed -r '/^4000/s/(.{136}).../\1036/' file

You can use the -i in place option with sed on your system, but it is best to then also specify...

That is correct, a dot in regex means "any character" .



--

Hi RudiC, IMO that was not a specification, but rather a remark. It says: which will be '000', therefore I used '...' instead..

If you compare the two sed scripts, the one with the -r option is way simpler (not that many escapes needed).
The \1 ("back reference") substitutes the 1. paranthesized regex part with itself.
In...

In fact, it's not a work around but one of the basic methods in data processing.

A day has 24 hours; you want to assign a certain value to each hour, a linear relationship that could be calculated has been rejected; so I put the desired values as defined by YOU into a 24 element...

Try
awk -F, 'BEGIN {split ("3,3,3,0,0,0,0,0,0,0,0,0,0,0,1,1,1,2,2,2,2,2,0", B); B[0] = 3} {print $1, "CUT " B[$2+0]}' file



EDIT: or, even better:

awk -F, 'BEGIN {split...

Lots of code here is less than ideal for purposes of brevity and using the tools available, but doing it in sed is just so pointlessly difficult, vs it being so laughably easy in awk, that I really...

sed doesn't really have comparisons, variables, expressions, or even numbers... It doesn't have anything you're asking it to do. You'd have to tell sed how to comprehend numbers in the form of many...

loose the double quotes - your cmptl_extr_list_file contains the file globbing that needs to be expanded by shell :

/bin/grep "$flnm_80BYTE" ${cmptl_extr_list_file}

1. an 2.print for loops over all the matches by /\b(\d{23})\b/g

/\[(\d+)\]/ and print $1 means if there is a match then print the first match
3.globally per line. And since this is done for...

Also with perl you could add boundary operators :
perl -nle '/\b(\d{23})\b/ and print $1'

Note that this code differs from other approaches, in the sense that it only prints the first occurrence...

To prevent consumption of leading digits you can exclude them from the leading pattern
sed -n 's/[^0-9]*\([0-9]\{23\}\).*/\1/p'

this is because the leading .* is greedy - it "chows" as many characters as possible (including numbers) and then "chows up" 23 numbers and then everything else till the end of the record/line...

Hi dsid

The single quotes are better at protecting the regular expression from the shell, than double quotes, so that is why I prefer to use them. When you read that they remove any meaning from...

-F defines field delimiters. In this particular case the field delimiters are [] as the 23-digit long string is surrounded by [].
We subtract 1 from $NF because the LAST field is following the ]....

Sed alternative

sed -n 's/.*\[\([0-9]\{23\}\)\].*/\1/p' filename

echo 'Original presentment record for ARN [24013935350549886999873] not found' | awk -F'[][]' '/^Original presentment/ {print $(NF-1)}'