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$
$ perl -le '@files = qw (file. file.TODAY.THISYEAR file.TODAY.LASTYEAR);
$TODAY = "140805"; $THISYEAR = "2014"; $LASTYEAR = "2013"; # should not be hard-coded
foreach $i...

#/bin/bash
while [ 0 ]
do
#if 0b file exists
if [ -e /ntwrk/common/backup_in_progress.txt ]
then
#Record the start time
tm=`date "+%Y%m%d %H%M"`
echo "$tm" >...

Try:awk -F"|" '$1!=a[$2]&&a[$2]{print b[$2];print}{a[$2]=$1;b[$2]=$0}' file

$sum=0; for i in `cat b22`
do
sum=`echo "$sum + $i" | bc`
done; echo $sum;
would have worked if you had changed $sum=0 on the first line to sum=0
I assume that the variable sum was not set when...

Will this do?
awk '/[1-9][0-9]* rows affected/' RS=\= infile

This should remove empty lines with any kind of whitespace..
awk NF file

Or use "continue":
for i in 1 2 3 4 5 6
do
if [ $i -eq 2 ]
then
continue #jump to element 3
else
echo $i
fi
done

Use -1 switch of ls instead of awk


#!/usr/bin/perl -w
use strict;
my $count=0;
my @list=`ls -1`;
print "@list";

You don't need '-n' option here.

Please post the output if the following command:

perl -e 'printf "%s --> %d\n", $_, -s for @ARGV' sam*

Depending on what you're trying to do, this could be a good use for lock files. There's a bunch of different ways you could do it. But based on the simplicity of your example, the easiest way would...

while [ 1 ]
do

processes_running=`ps -fu <username>|grep -e "$JOBNAME" |grep -v grep|wc -l`
if [ $processes_running -ge 1 ]
then

<whatever you want do if jobname is running>

else
...