Search Results

/etc/services lists what (default) ports are mapped to which services. There are various commands (netstat, telnet, nmap, etc.) to help identify which ports are open.

A shell variable name must begin with alphanumeric character or underscore character followed by one or more alphanumeric or underscore characters.

So try without that period:-
zone_5.org

Try this
df -h | awk '$5+0 > 45'
If it doesn't work, provide the output of df -h

And in Solaris, use nawk

Unless you are root on the remote server, su will ask for a password. So I don't quite get what you are seeing.

Try this:
ssh -t usera@hosta sudo 'su - userb -c id'

Thats exactly what Jim said in post #2
I understand you ar not root then... You will have to see with your admins if then can correct the sudoers files for your requirement...

You can cram as many directories as you want into one find, no need to run it repeatedly. You may wish to redirect stderr in case some of them don't exist ... 2>/dev/null

VAR="$(ssh -T -i /home/buddy/.ssh/id_rsa buddy@ginger find ${the_path} -name "*.jpg" '|' wc -l)"

You might like... ;o)
Much related you could try this as an added extra:-
Last login: Mon Sep 30 19:34:05 on ttys000
AMIGA:barrywalker~> clear; star=""; i='-\|/*'; for k in {0..9}; do for j in...

The backticks have been deprecated in favor of $() for command substitution because $() can easily nest within itself as in $(echo foo$(echo bar)). There are also minor differences such as how...

And if possible, replace all back tics `` with parentheses $()
if ! [ $(uptime | grep -q day) ]

Try replacing if [ ! `uptime | grep day` ] with


if ! [ `uptime | grep -q day` ]

Actually, that is extended pattern matching, not a regular expression.

A pattern-list is a list of one or more patterns separated from each
other with a & or |. A & signifies...

This may be it :awk '/https:\/\// {gsub (/https:\/\//, ""); print}' file
www.amazon.com
www.google.com

$ sed "s#^https://##" file
www.amazon.com
Help.com
www.google.com
http://www.bbc.com


Or


$ sed "s#^[^/]*//##" file
www.amazon.com
Help.com
www.google.com
www.bbc.com

function function1() {
case $1 in
1) do something ;;
2) do other something ;;
[3-9]) do some other something ;;
esac
}

call it with function1 $opt1

Better way, using pure shell builtins and splitting on array elements:
printf "%s\n" "${ARRAY[@]}"

#!/bin/ksh
arrayname=(1 2 3 4 5)
echo ${arrayname
} | tr " " "\n"

Try:
for z in $x
do
case $y in
*$z*) echo "a pattern in \$y matches any pattern in \$x"; break
esac
done

Recent kshs (as well as bashes) provide a regex match in conditional expressions. man ksh:So your code could read:x="aa bb cc dd ee ff gg hh ii jj kk ll"
y="ff kk"
$ for z in $x; do [[ "$y" =~...

If 'pattern' stands for 'word' and 'match' for 'is equal to', then nested loops seem most correct.
for x1 in $x; do
for y1 in $y; do
if [ "$x1" = "$y1" ]; then
echo "$x1"
fi
done
done

#!/usr/bin/ksh

hostname="${1}"

if [[ "${hostname}" = @(red|black|green|yellow|blue) ]] ; then
echo "${hostname} - match"
else
echo "${hostname} - no match"
fi