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The problem is that:

*i--;

decrements the pointer, not the pointed-to value. I.e. it's equivalent to:


*(i--);


What you really want is:


(*i)--;


(On my machine at least, your...

#!/usr/bin/perl
#
#
use strict;

my $str = "a_b c[10_9]";
for($str) {
s/ /_/;
s/(.+)_/$1:/;
}
print "$str\n";
exit(0);

./testme.pl
a_b_c[10:9]

...

$var ~= s/ /_/;

static means it has all of the external libraries "internal" - so it never has to worry about library versions being correct. These image files are huge and use a lot of memory. Image activation...

The traditional virtual mapping for the kernel in linux x86 is 1 gig of address space for the kernel, 3 gigs of address space for one process. There's also a 128-meg hole punched into the kernel...

You'd define the type of the struct in the header file, and declare (but not define) MEM_IO_PTRS in the header using extern:


/* in header file */

struct mem_ptrs
{
... /* members */
};...

I see! In which case you might find man 2 syscall a better way to do arbitrary syscalls. I've certainly never managed to get _syscall3 and the like to work...

1. yes, the kernel can issue asyncronous interrupts. In UNIX they amount to signals. The kernel also preempts processes in what is known as a process context switch. i.e., another process gets the...

Yes... and why do you need 0xcf8? Can you not obtain the information you need through the kernel itself?

First, you get a useless use of cat award (http://partmaps.org/era/unix/award.html).

Secondly, because find doesn't work that way. By default it expects paths to look inside, not file names; ...