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Using a while loop seems easiest:


i=
while [[ -z $i ]] # while i is empty
do
printf "enter integer: "
read i
if [[ -z ${i//[0-9]/} ]] #true when i has all digits
...

Please, can you give further details about what you need? Then, maybe one of us can help you...

In a single command:


today=$( date | tr "[a-z]" "[A-Z]" )

Using parameter expansion in bash 4.x
today=$(date)
today="${today^^}"