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With GNU date, you can do something like this, in sh or bash:
#!/bin/sh

# Past date in seconds since Epoch
past=$(date +%s --date "12/02/2013 11:21")

# Now in seconds since Epoch
now=$(date...

Nothing fancy in the below script, just an all-in-one task:
awk '{$10=$7;$7=$8=$9="na"}
$10~/aa1/{$7="aa1"}
$10~/ab2/{$8="ab2"}
$10~/ac3/{$9="ac3"}
1' input_file > output_file

Try this one instead :
awk -F, '{A[$1 FS $2] = A[$1 FS $2] ? A[$1 FS $2] FS $NF : $N} END {for ( k in A ) print A[k]}' output/* > output-4.csv

Try also this awk code as well :awk 'NR==FNR{A[++i,1]=$1;A[i,2]=$2;A[i,3]=$3;next}
{j=0;while(j++<i)if(($2==A[j,1])&&($3>=A[j,2])&&($3<=A[j,3]))print}
' filterfile datafile

Edit - Nevermind, don't pay attention to this stupid question.


Is it acceptable to use a range file like this?

Actually, Scrutinizer's reply is way more simple to use :)
if ! $SERVICE status > /dev/null 2>&1uses exit status as well; in this case if $SERVICE status did not (!) exit with status 0; then rest of...

Thanks Corona688 for your input !
Here is another solution using AWK:
~/unix.com$ awk '{gsub("\r","");print > "file"$NF".txt"}' RAW

awk '{print > "file"$NF".txt"}' RAW

awk '{print > $3".txt"}' EDIT.txt

awk '{print > $NF".txt"}' RAW

Actual Debian Testing (Jessie) also uses gawk after a "standard system" install.
You still get mawk if you choose to not install the "Standard system" at Tasksel install step.

Here is a solution using awk:~/unix.com$ awk 'int(100*rand())%5<1' file
5 and 1 are the parameters you want to modify here : 1/5 = 20% in this example

To be more specific in your...

\r is added by your text editor (Windows text editor?) at the end of each line (carriage return (http://en.wikipedia.org/wiki/Carriage_return#Typewriters))
You have to configure it to NOT write \r...

Try this then (could not test my previous code 'cause I was on my smartphone)awk '!($0~x)' x="$3" file

Try this
~/unix.com$ awk -F\| 'gsub(/ /,"|")&&$4=$4?$4:"NULL"{print $1,$4}' f
The above script is overcomplicated, use Corona688's or in2nix4life's suggestion instead :p

From your sample code, it's impossible to find CDR3 on second and fourth line (ID 1 & 3). Is there any [tab] and [spaces] mixed?

It's not sed but you can try this:
~/unix.com$ awk '!A[$0]++' file

One way :
~/unix.com$ awk 'NR==FNR{A[$1]++;next}A[$1]==2' file.txt file.txt

Which shell are you using?

In sh, dash, should run on bash as well:
#!/bin/sh

if [ ! "$1" ]; then
TEXT="Data_0"
else
TEXT="$1"
fi

if [ ! "$2" ]; then
Lines=45
else
Lines=$2
fi

A bit straightforward, but it should do the trick, at least on the sample you provided:
~/unix.com$ awk -F'=' '/NAME/{n=$2}/TARGET/{t=$2}/STATE/{s=$2}{if(s&&t&&(s!=t)){s="";t="";print n}}' file...

#!/bin/bash
sum=0
for i in $@; do sum=$((sum+i)); done
echo $sum
exit 0~/unix.com$ bash script 4 5 6 7
22
See man bash (https://www.unix.com/man-page/All/1/bash/) for more infos

Another way:~/unix.com$ d='/root/logs/testing/today/'; echo ${d%/*/}
/root/logs/testing

Here is a start (it's #!/bin/sh, but it should run with bash too):#!/bin/sh

FS='|'
file=; while [ "$file" != 'done' ]; do
[ "$file" ] && files="$files$file$FS"
read -p 'What is the name of...

~/unix.com$ awk -v var='( |^)a:2( |$)' '$0~var{getline x;getline;print x RS $0}' file
a
b
~/unix.com$ grep -A2 '\( \|^\)a:2\( \|$\)' file
b:2 a:2
a
b

~/unix.com$ grep -Ff f2 f1
The reverse:~/unix.com$ grep -vFf f2 f1
In awk, based on Corona688's solution:
~/unix.com$ awk 'NR==FNR{A[$1]=1;next}A[$2]' f2 f1
The reverse:~/unix.com$ awk...

Here is it, but i'm still not sure about output file (my awk script below cat file2 to output (print>>"output")
the notmatched file contains the unmatched strings from file1
~/unix.com$ awk...