All memory is backed by swap whether it's needed right this moment or not. So the swap space isn't actually being used at present -- but if memory became short, everything already has preallocated locations in swap to get dumped into.
All memory is backed by swap whether it's needed right this moment or not. So the swap space isn't actually being used at present -- but if memory became short, everything already has preallocated locations in swap to get dumped into.
That used to be the way swap was handled with SunOS 4 but it is no more with Solaris 2 and newer. While it is still recommended to have some swap set, a swap area isn't technically required on Solaris.
---------- Post updated at 22:47 ---------- Previous update was at 22:25 ----------
Quote:
Originally Posted by redstone
I'm getting confused by swap
You need to know that swap means two different concepts here.
"swap -l" shows the size of the swap area, i.e. a dedicated storage area where the OS can paginate memory pages from/to RAM.
Your swap area size is 32 GiB and all free.
"swap -s" shows virtual memory statistics.
You virtual memory size is 34 GiB, this includes 32 GiB of swap area plus 2 GiB of RAM. The command tells 6.7 GiB are really allocated as reserved memory doesn't use RAM or swap.
There is then a contradiction between both of these commands.
Can you re-run both of these commands and post also the last lines of
Code:
prstat -Z
and
Code:
echo ::memstat | mdb -k
commands.
Last edited by jlliagre; 03-21-2012 at 11:58 AM..
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