Splitting a line with pattern in Sed - Unix


 
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# 8  
Old 09-23-2011
Code:
sed 's/\([0-9ABC]\{11\}^\)/\n\1/g'

For two lines in stead of 8. Assuming you always have 8....

Code:
sed 's/\([0-9ABC]\{11\}^\)/\n\1/5'

The above will insert the newline (\n) before the 5th occurrence of a string of 11 characters from 0-9 and A, B and C followed by one ^.
# 9  
Old 09-23-2011
Thanks. But it's not always 8 lines. It can have n number of lines
# 10  
Old 09-23-2011
This will probably take some pre-work.

I imagine:

Counting the number of "fields" in each line and pre-pending it to the lines using awk -F^ '{print NF, $0}'

Parsing the file line by line in a script
Letting the "script" adjust the sed command above using some math, such as

Code:
cat $INPUTFILE | awk '{print (NF/2)+1,$0}' | while read CUTPOINT REMAINDER
do
  echo $REMAINDER | sed 's/\([0-9ABC]\{11\}^\)/\n\1/'${CUTPOINT}
done

I have not checked whether Linux' stupid read function accepts input from a while loop. I seem to recall that it doesn't.

Regardless that can be worked around. More concerning is that sed is instantiated for every line from the original input file.
# 11  
Old 10-02-2011
I am able to figured it out.

Thanks
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