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Hopefully an Easy Question

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# 1  
Old 05-31-2007
Hopefully an Easy Question
I have a file name in this format

ABC_WIRE_TRANS_YYYYMMDD_00.DAT

I need to cut out the _00 out of the file name everytime. It could be _00, _01,_02, etc ....

How do I cut it out to look as follows?

ABC_WIRE_TRANS_YYYYMMDD.DAT
# 2  
Old 05-31-2007
A possible solution :
Code:
$ echo ABC_WIRE_TRANS_YYYYMMDD_00.DAT | sed 's/_[0-9][0-9]\././'
ABC_WIRE_TRANS_YYYYMMDD.DAT
$

Jean-Pierre.
# 3  
Old 05-31-2007
Sorry
The letters YYYYMMDD are actually going to be a date 20070531. So that will not work.
# 4  
Old 05-31-2007
Actually aigles solution would work. To make it look better.
Code:
echo ABC_WIRE_TRANS_YYYYMMDD_00.DAT | sed 's/_..\.DAT/.DAT/g'

# 5  
Old 05-31-2007
A little bit more secure:
Code:
echo ABC_WIRE_TRANS_YYYYMMDD_00.DAT | sed 's/__[0-9][0-9]\.DAT$/.DAT/g'

Jean-Pierre.
# 6  
Old 05-31-2007
just one way, assuming extension .DAT or other 3 letter extension
Code:
#string="ABC_WIRE_TRANS_YYYYMMDD_00.DAT"
#echo ${string%_*DAT}${string:(-4)}
ABC_WIRE_TRANS_YYYYMMDD.DAT

# 7  
Old 05-31-2007
Thx
thanks for your help
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