RE_COMP(3) Linux Programmer's Manual RE_COMP(3)NAME
re_comp, re_exec - BSD regex functions
SYNOPSIS
#define _REGEX_RE_COMP
#include <sys/types.h>
#include <regex.h>
char *re_comp(const char *regex);
int re_exec(const char *string);
DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the
pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's
contents are not altered.
re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex.
RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message.
re_exec() returns 1 for a successful match, zero for failure.
ATTRIBUTES
For an explanation of the terms used in this section, see attributes(7).
+---------------------+---------------+-----------+
|Interface | Attribute | Value |
+---------------------+---------------+-----------+
|re_comp(), re_exec() | Thread safety | MT-Unsafe |
+---------------------+---------------+-----------+
CONFORMING TO
4.3BSD.
NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead.
SEE ALSO regcomp(3), regex(7), GNU regex manual
COLOPHON
This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the
latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.
GNU 2017-09-15 RE_COMP(3)
Check Out this Related Man Page
RE_COMP(3) Linux Programmer's Manual RE_COMP(3)NAME
re_comp, re_exec - BSD regex functions
SYNOPSIS
#define _REGEX_RE_COMP
#include <sys/types.h>
#include <regex.h>
char *re_comp(const char *regex);
int re_exec(const char *string);
DESCRIPTION
re_comp() is used to compile the null-terminated regular expression pointed to by regex. The compiled pattern occupies a static area, the
pattern buffer, which is overwritten by subsequent use of re_comp(). If regex is NULL, no operation is performed and the pattern buffer's
contents are not altered.
re_exec() is used to assess whether the null-terminated string pointed to by string matches the previously compiled regex.
RETURN VALUE
re_comp() returns NULL on successful compilation of regex otherwise it returns a pointer to an appropriate error message.
re_exec() returns 1 for a successful match, zero for failure.
ATTRIBUTES
For an explanation of the terms used in this section, see attributes(7).
+---------------------+---------------+-----------+
|Interface | Attribute | Value |
+---------------------+---------------+-----------+
|re_comp(), re_exec() | Thread safety | MT-Unsafe |
+---------------------+---------------+-----------+
CONFORMING TO
4.3BSD.
NOTES
These functions are obsolete; the functions documented in regcomp(3) should be used instead.
SEE ALSO regcomp(3), regex(7), GNU regex manual
COLOPHON
This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the
latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.
GNU 2017-09-15 RE_COMP(3)
Hello
I need to make a regex.
I have a file myfile, in this file I want to find a number situated after PAYSLOT=
Before PAYSLOT is the begining of line (I guess ^) and
after the number is the end of line (I guess $) .
I want to echo this number (I guess $1) and put it in my variable payslot.... (5 Replies)
Hi guys,
Pretty new to regex, and i know im doing something wrong here. I'm trying to get a regex command that restricts a string to be 8 characters long, and the first character cannot be 0. Here's what i have so far...
echo "01234" | grep "^{8}*$"
Thanks very much!
-Crawf
... (7 Replies)
Hi,
I can't get this script ot work and I wa wondering if anyone could help?
I need to open a file and use a subroutine to search each line for a regular expression. If it matches then I need to return a match from the subroutine and print the result?
Any help would be greatly... (11 Replies)
Morning folks,
I need help with the following issue:
Let's say we I have the following output:
First Name: Test
Last Name: Test2
Number: T1234
Number2: T1234
Needed Output:
T1234
Now I want to grep/nawk/printf/sed out the Number: (13 Replies)
Hi,
I have a file with some words divided into syllables by the character "|" (pipe).
For example zu|ri|ghe|se.I would like a regex that matches all the words that are not divided in syllables.All the word that have no "|" pipe character.I have thought at
$echo "zu|ri|ghe|se" | grep ''
... (7 Replies)
I have got numbers like
l255677
l376039
l188144
l340482
l440700
l254113
to match the numbers starting with '13' what would be the regex
=~/13(.*)/ =======>This is not working ....
But for user123,user657
regex =~/user(.*)/ ========>works
Thanks for help..!! (7 Replies)
Hi all
I am struggling to find out the capturing regex of a date format such as 10/12/2009. Also I need help on how to assign the date(i.e, 10/12/2009 ) to a variable after the match is found using the capturing regex.
Any help is appreciated. Thanks in advance. (5 Replies)
What do you think of this regex to match IP address? I have been reading up on regex and have seen some really long ones for IP. Would this fail in any scenarios?
(+\.){3}* (5 Replies)
Need some help with a regex if loop problem.
File1:
2323
3232
4230
3230
4340
4343
233
32320
I want to print "Zero" if the number ends with a zero, but print "number" if it does not!
#!/bin/bash
/usr/bin/nawk '{
if ($1 ==/+0\b/){
print "Zero"}
else{
print "number"} (5 Replies)
hi,
i need my bash script to find regex in xml file.. and comment 2 lines before and after the line that contains regex.. can't use # needs to be <!-- at the beginning and --> and the end of the comment.
so eg..
first block
<filter>
<filter-name>MyRegEx</filter-name>
... (11 Replies)
Hi,
I have a file like this-
regex
1
2
regex
2
4
5
regex
4
6
8
regex
how do I split each interval to a new file? something like-
file1-1
2
file2-2 (7 Replies)
Hi Experts,
I am using ls with regex in the below manner:
VAR="*.txt *.TXT"
ls -l $VAR
This is working fine if I have both txt and TXT extension files in my directory. But if any of them is not present, its throwing errors, that *.TXT file not found in the directory. So what am i missing... (6 Replies)
I've been using the following regex below in a bash script on RHEL 5.5 using version
GNU bash, version 3.2.25(1)-release
I've tried using the script on RHEL 6.3 which uses GNU bash, version 4.1.2(1)-release
I assume there's been alot of changes to bash since that's quite a jump in revisions.... (12 Replies)