Linux and UNIX Man Pages

Linux & Unix Commands - Search Man Pages

gregoriantojd(3) [php man page]

GREGORIANTOJD(3)							 1							  GREGORIANTOJD(3)

gregoriantojd - Converts a Gregorian date to Julian Day Count

SYNOPSIS
int gregoriantojd (int $month, int $day, int $year) DESCRIPTION
Valid Range for Gregorian Calendar 4714 B.C. to 9999 A.D. Although this function can handle dates all the way back to 4714 B.C., such use may not be meaningful. The Gregorian calendar was not instituted until October 15, 1582 (or October 5, 1582 in the Julian calendar). Some countries did not accept it until much later. For exam- ple, Britain converted in 1752, The USSR in 1918 and Greece in 1923. Most European countries used the Julian calendar prior to the Grego- rian. PARAMETERS
o $month - The month as a number from 1 (for January) to 12 (for December) o $day - The day as a number from 1 to 31 o $year - The year as a number between -4714 and 9999 RETURN VALUES
The julian day for the given gregorian date as an integer. EXAMPLES
Example #1 Calendar functions <?php $jd = GregorianToJD(10, 11, 1970); echo "$jd "; $gregorian = JDToGregorian($jd); echo "$gregorian "; ?> SEE ALSO
jdtogregorian(3), cal_to_jd(3). PHP Documentation Group GREGORIANTOJD(3)

Check Out this Related Man Page

CAL_FROM_JD(3)								 1							    CAL_FROM_JD(3)

cal_from_jd - Converts from Julian Day Count to a supported calendar

SYNOPSIS
array cal_from_jd (int $jd, int $calendar) DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $jd - Julian day as integer o $calendar - Calendar to convert to RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and the date in string form "month/day/year". EXAMPLES
Example #1 cal_from_jd(3) example <?php $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003)); print_r(cal_from_jd($today, CAL_GREGORIAN)); ?> The above example will output: Array ( [date] => 8/16/2003 [month] => 8 [day] => 16 [year] => 2003 [dow] => 6 [abbrevdayname] => Sat [dayname] => Saturday [abbrevmonth] => Aug [monthname] => August ) SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3). PHP Documentation Group CAL_FROM_JD(3)
Man Page

15 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Date Intervals

I posted a question on date intervals about a month back asking about how I could be able to go about a user entering the starting year/month/day and an ending year/month/day and then the script automatically cycling through each day of each month of each year that the user has specified. I... (7 Replies)
Discussion started by: yongho
7 Replies

2. Shell Programming and Scripting

convert Julian date to calender date

Hi, I have script in unix which creates a julian date like 126 or 127 I want convert this julian date into calender date ex : input 127 output 07/may/2007 or 07/05/2007 or 07/05/07 rgds srikanth (6 Replies)
Discussion started by: srikanthus2002
6 Replies

3. Shell Programming and Scripting

how to assign the first day of the next month

Hi everybody, I am very new in shell and this is my first post :). i am trying to write a script in which i want to decide some begin dates. this dates will be used by another shell scripts. i would like to assign: 1- a variable which is a = sysdate 2- another variable b = the first day of... (6 Replies)
Discussion started by: rosalinda
6 Replies

4. Shell Programming and Scripting

Perl in KSH - julian conversion

Hello Everyone, I have this code misbehaving in one of my scripts, I have a var containing the sequential number of the day for the year and I am suppose to get the regular date for that day and its weekday. If I set the day to 273 I get back 2008/09/31 which is not a proper date. can you help... (7 Replies)
Discussion started by: gio001
7 Replies

5. Shell Programming and Scripting

append a line into a file in the top

hi, My code is #!/bin/sh echo "\n\nPlease enter the month of the year(YYYYMM) : \c" read date_rep INPUT_L9_FILE=L9_Recharge_Description_EOM_$date_rep.csv #This part is used to summarise Grand_Total, Balance_Total of file L9_Recharge_Description_EOM_${1}.csv. awk -F"," '{if(NR!=1)... (5 Replies)
Discussion started by: madfox
5 Replies

6. Shell Programming and Scripting

Get current day on Julian date format

Hi guys, I know if I try to get a julian date using a specific date I can but I try to get the current date I got an error as you can see below: This one works fine: date -d "2010/10/30" +%j But I can't get the current date as below: `date -d "+%Y/%m/%d`" +%j Does somebody can... (6 Replies)
Discussion started by: edudiogo
6 Replies

7. Shell Programming and Scripting

Awk convert from day of year to date

Hello everyone, I have a file which has day of year in one of the columns (JD=substr($0,72,3)). The bellow scripts shows me the minimum and maximum values of the JD and I would like to convert the JD to date. #!/bin/gawk -f { check=substr($0,1,1) if (check == "S") { ... (6 Replies)
Discussion started by: alex2005
6 Replies

8. Shell Programming and Scripting

Issue in Julian date conversion

All, I am facing an issue with julian date conversion.. current command: echo `date +%Y%j` `cat -n /home/user/FILENAME.dat |awk '{printf "%08s", $2}'` The above command is working good. But in the above bolded part, it is converting system date to julian date. However I want to... (8 Replies)
Discussion started by: cmaroju
8 Replies

9. UNIX for Dummies Questions & Answers

[SOLVED] how to extract the day and month from a user supplied date ?

Hi All , I am trying to extract the day and month from a user supplied date . But not able . Please help . This is what I am trying to do , I have followed other articles in this scenario. userdate=$1 echo "Script parameter userdate is $userdate" The output of this is in this... (7 Replies)
Discussion started by: megha2525
7 Replies

10. UNIX for Dummies Questions & Answers

How to get year part from file created date?

Hi Gurus, I need to get year part of file created date. when using ls -l , it only show month, day and time. is there any option I can add to get year portition? Thanks in advance (7 Replies)
Discussion started by: ken6503
7 Replies

11. UNIX for Advanced & Expert Users

Find all files other than first two files dates & last file date for month

Hi All, I need to find all files other than first two files dates & last file date for month and month/year wise list. lets say there are following files in directory Mar 19 2012 c.txt Mar 19 2012 cc.txt Mar 21 2012 d.txt Mar 22 2012 f.txt Mar 24 2012 h.txt Mar 25 2012 w.txt Feb 12... (16 Replies)
Discussion started by: Makarand Dodmis
16 Replies

12. Shell Programming and Scripting

How to find all files other than first two dates & last date per month and year?

how to find all files other than first two dates & last date per month and year Hi All, lets say there are following files in directory -rwxr-xr-x 1 user userg 1596 Mar 19 2012 a.txt -rwxr-xr-x 1 user userg 1596 Mar 19 2012 b.txt -rwxr-xr-x 1 user userg ... (6 Replies)
Discussion started by: Makarand Dodmis
6 Replies

13. Shell Programming and Scripting

Day/Hour diff between two date

Dear All I need to find out day diff between two dates. date -d or date -- day is not working in mine system. Currently i am using below code but it gives me wrong value while month change. IP: Date 1: 20150802 11:30:45 Date 2: 20150728 16:30:45 code used: awk '{t1=$2; t2=$4;... (7 Replies)
Discussion started by: jaydeep_sadaria
7 Replies

14. Shell Programming and Scripting

Adding one day to a date

Hi All, I want to add one day to a date and store it in a variable. From GUI we are passing value (last day of the month)to $t_date. This $t_date will give me the value like this %Y%m%d 20150531. Now I want to add one day to this value and store it in a variable "datein". datein should... (8 Replies)
Discussion started by: ROCK_PLSQL
8 Replies

15. Shell Programming and Scripting

Else if in awk

Hi All, my input file is comma delimited. 1,Y,1111,9999 2,Y,1,9999 2,N,1,9999 2,Y,9999,9999 o/p should be 1,Y,1112,9999 2,Y,0002,9999 2,Y,0000,9999 scenario is 1.if $2 is "N" then exit. 2.if $3 is not equal to $4 then increment $3 by 1 padding to four decimal places to the left.... (6 Replies)
Discussion started by: looney
6 Replies