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Capturing regex of perl

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# 1  
Old 12-17-2009
Capturing regex of perl
Hi all

I am struggling to find out the capturing regex of a date format such as 10/12/2009. Also I need help on how to assign the date(i.e, 10/12/2009 ) to a variable after the match is found using the capturing regex.
Any help is appreciated. Thanks in advance.
# 2  
Old 12-17-2009
Try

Code:
$_ = "Today is 17/12/2009  Tuesday";
print "Date is $1" if /([0-3][0-9]\/[0-1][0-9]\/[0-9[0-9][0-9][0-9])/;

# 3  
Old 12-17-2009
Thanks a lot it worked. But I am facing another problem when I want to assign another date formats (i.e., July 1, 1887 and 2000.10.17) in the similar fashion to $2 in continuation of first problem. Any help please.
Last edited by my_Perl; 12-17-2009 at 07:21 AM.. Reason: Problem modified
# 4  
Old 12-17-2009
Hi , I suggest you to check http://www.perl.com/lpt/a/718
Regards
# 5  
Old 12-17-2009
I am unable to capture the second date format with $2 using the regex. However it works only with $1. My problem on using multiple variables $1, $2 etc for different formats. Please help.
# 6  
Old 12-17-2009
Code:
$
$ cat -n dates.txt
     1  12/17/2009
     2  July 1, 1887
     3  2000.10.17
$
$ ##
$ perl -lne 'print;
>            if (/(\d{2})\/(\d{2})\/(\d{4})/){
>              printf("\tDay   = %s\n\tMonth = %s\n\tYear  = %s\n",$2,$1,$3)}
>            elsif (/(\w+) (\d+), (\d{4})/) {
>              printf("\tDay   = %s\n\tMonth = %s\n\tYear  = %s\n",$2,$1,$3)}
>            elsif (/(\d{4})\.(\d{2})\.(\d{2})/) {
>              printf("\tDay   = %s\n\tMonth = %s\n\tYear  = %s\n",$3,$2,$1)}
>           ' dates.txt
12/17/2009
        Day   = 17
        Month = 12
        Year  = 2009
July 1, 1887
        Day   = 1
        Month = July
        Year  = 1887
2000.10.17
        Day   = 17
        Month = 10
        Year  = 2000
$
$

tyler_durden
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