Shell Programming and Scripting

hi
I m trying to display the processes of each user but its coming in one line like

george wilkins
PID TTY TIME CMD 7661 ? 00:00:01 sshd 7662 pts/6 00:00:00 bash
i want the output to be like
PID TTY TIME CMD
7661 ? 00:00:01 sshd
7662 pts/6 00:00:00 bash

my code is

proc=$(users)
for i in $proc
do
echo $(cat /etc/passwd | grep "$i" | cut -d ':' -f 5)
echo $(ps -u $i)
done

any idea how can i make it as a list
thanks

for i in `users`
do
cat /etc/passwd | grep \^"$i:" | cut -d ':' -f 5
ps -u $i
done


i.e. Put the output to standard output rather than into a shell variable.
The modified grep gives an exact match on username in the first field in passwd (e.g fred and freddy won't gove false matches).

sorry its still not working..My Question is to diplay the processes in line for each user
but its displaying in one line
PID TTY TIME CMD 10886 ? 00:00:00 sshd 10887 pts/3 00:00:00 bash
like this

thanks guys i got the soln
echo $(ps –u $i)
to:
echo “$(ps –u $i)”

Try this !!!

Code:

who|while read x ;
do
ps -u $x
done

You can also direct each o/p into separate files.

Code:

nawk '{
for(i=1;i<NF/4;i++)
{
	printf $1" "$2" "$3" "$4" "
	for(j=(i*4+1);j<=(i+1)*4;j++)
		printf $j" "
	print ""
}
}' file