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awk for a line that contains someting in a field

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# 1  
Old 03-16-2011
awk for a line that contains someting in a field
How would I do something like this when field 4 contains "John". I only want to print field 1 and 4 when when field 4 contains"John".

Code:
awk -F" " '{print $1 $4}

# 2  
Old 03-16-2011
Quote:
Originally Posted by COKEDUDE
How would I do something like this when field 4 contains "John". I only want to print field 1 and 4 when when field 4 contains"John".

Code:
awk -F" " '{print $1 $4}

Code:
# $4 contains John
awk '$4 ~ "John" {print $1, $4}' myFile
# $4 is John
awk '$4 == "John" {print $1, $4}' myFile

These 2 Users Gave Thanks to vgersh99 For This Post:
cokedude dagamier
# 3  
Old 03-16-2011
Code:
$ cat  file
$4 is contains John
dsf

$ ruby -ane 'print if $F[3] =~ /John/i' file
$4 is contains John

# 4  
Old 03-16-2011
Quote:
Originally Posted by vgersh99
Code:
# $4 contains John
awk '$4 ~ "John" {print $1, $4}' myFile
# $4 is John
awk '$4 == "John" {print $1, $4}' myFile

Thank you. My mistake was I was putting this $4 == "John" in the wrong place like this.

Code:
awk '{$4 == "John" print $1, $4}' myFile

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