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Replace part of folder(s)

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# 1  
Old 04-27-2013
Replace part of folder(s)
I have a script that will output folders that all end with "x.deb".

I want a shell script snippet that removes the "x.deb" from all those folders.

Thanks in advance.
# 2  
Old 04-27-2013
What do you mean by removes? Are you just interested in modifying a stream of text? Or are you trying to rename directories?

What have you tried?

Regards,
Alister
# 3  
Old 04-27-2013
Code:
for old in *x.deb; do
  if [ -d "$old" ]; then
    new=$(echo "$old" | sed "s/x\.deb$//")
    mv "$old" "$new"
  fi
done

# 4  
Old 04-28-2013
@hanson44, no need to use external utility: sed for performing substitution.

You can use built-in parameter substitution instead in any POSIX shell:
Code:
for name in *x.deb
do
        [[ -d "$name" ]] && mv "$name" "${name%%x.deb}"
done

# 5  
Old 04-28-2013
Quote:
no need to use external utility
I know. Smilie
# 6  
Old 04-28-2013
For POSIX you would need single brackets.

Also, a single percent-sign would work here and the loop can be made to on only use directory entries, so it would involve fewer iterations and only a test if the name exists, to avoid an error in case there are no directories with that pattern. Further, the mv command needs to be protected from commands that begin with "-". So, either:

Code:
for name in *x.deb/
do
  [ -e "$name" ] && mv -- "$name" "${name%x.deb/}"
done

or

Code:
for name in ./*x.deb/
do
  [ -e "$name" ] && mv "$name" "${name%x.deb/}"
done


--
In bash there is a nullglob option::
Code:
shopt -s nullglob
for name in ./*x.deb/
do
  mv "$name" "${name%x.deb/}"
done

Last edited by Scrutinizer; 04-28-2013 at 12:42 PM..
# 7  
Old 04-29-2013
I'm sorry to tell you this, however it seems as if none of the above work.

The folders I have:

The "test.x.deb" folders don't rename after running either script...
Last edited by pasc; 04-29-2013 at 09:20 AM..
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