Help with calling to file for a username and password combo
Hokay...first post, and I have been doing Linux scripting for a total of 2 days now. I think I am doing pretty well, but awk and arrays(what I think I need here) is a bit above me so far.
I have written a script that will take and either create or modify 5 users, and passwords.
It checks the device to see if a user exists, if they don't, it adds the user, and gives them sudo access, and changes the password to the one specified. If they do exist, it changes the password to the specified password, and then checks for sudoers access, and gives the user access if they don't have it.
Currently this script isn't really scaleable. it us for 5 users. It can be tweaked to add more, but I know there is a better way to do it, I just don't know how at my level of knowledge.
What I want to have it do, is call to a text file that has something like
username password
username password
username password
And have set the username and password on each line, on loop, till EOF. I don't know how to do that, and have it keep username on line1 with username on line1, and username on line2 with username on line2 successfully.
I have already seen a few ways I can clean up the existing code and make it cleaner, but I am trying to get this part figured out before tomorrow night first.
If you have any help, please let me know.
Here is my current script: (it is much cleaner than how it pasted in here)
Code:
#!/bin/sh
user1=blah
user2=blahette
user3=blahjr
user4=mrblah
user5=blaaaaaaaa
password1=adsfasdfaf
password2=asdfasdfasd
password3=asdfasdfasd
password4=asdfadsf
password5=asdfasd
createuser1(){
useradd -m $user1
sh -c "echo '$user1 ALL=(ALL) ALL' >> /etc/sudoers"
echo -e "$password1\n$password1" | (passwd --stdin $user1)
}
changepass1(){
addroot(){
sh -c "echo '$user1 ALL=(ALL) ALL' >> /etc/sudoers"
echo $user1 "has been given root access"
}
printroot(){
echo $user1 already has root access
}
echo -e "$password1\n$password1" | (passwd --stdin $user1)
if [ `grep $user1 /etc/sudoers | wc -l` -lt "1" ];
then addroot
else printroot
fi
}
createuser2(){
useradd -m $user2
sh -c "echo '$user2 ALL=(ALL) ALL' >> /etc/sudoers"
echo -e "$password2\n$password2" | (passwd --stdin $user2)
}
changepass2(){
addroot(){
sh -c "echo '$user2 ALL=(ALL) ALL' >> /etc/sudoers"
echo $user2 "has been given root access"
}
printroot(){
echo $user2 already has root access
}
echo -e "$password2\n$password2" | (passwd --stdin $user2)
if [ `grep $user2 /etc/sudoers | wc -l` -lt "1" ];
then addroot
else printroot
fi
}
createuser3(){
useradd -m $user3
sh -c "echo '$user3 ALL=(ALL) ALL' >> /etc/sudoers"
echo -e "$password3\n$password3" | (passwd --stdin $user3)
}
changepass3(){
addroot(){
sh -c "echo '$user3 ALL=(ALL) ALL' >> /etc/sudoers"
echo $user3 "has been given root access"
}
printroot(){
echo $user3 already has root access
}
echo -e "$password3\n$password3" | (passwd --stdin $user3)
if [ `grep $user3 /etc/sudoers | wc -l` -lt "1" ];
then addroot
else printroot
fi
}
createuser4(){
useradd -m $user4
sh -c "echo '$user4 ALL=(ALL) ALL' >> /etc/sudoers"
echo -e "$password4\n$password4" | (passwd --stdin $user4)
}
changepass4(){
addroot(){
sh -c "echo '$user4 ALL=(ALL) ALL' >> /etc/sudoers"
echo $user4 "has been given root access"
}
printroot(){
echo $user4 already has root access
}
echo -e "$password4\n$password4" | (passwd --stdin $user4)
if [ `grep $user4 /etc/sudoers | wc -l` -lt "1" ];
then addroot
else printroot
fi
}
createuser5(){
useradd -m $user5
sh -c "echo '$user5 ALL=(ALL) ALL' >> /etc/sudoers"
echo -e "$password5\n$password5" | (passwd --stdin $user5)
}
changepass5(){
addroot(){
sh -c "echo '$user5 ALL=(ALL) ALL' >> /etc/sudoers"
echo $user5 "has been given root access"
}
printroot(){
echo $user5 already has root access
}
echo -e "$password5\n$password5" | (passwd --stdin $user5)
if [ `grep $user5 /etc/sudoers | wc -l` -lt "1" ];
then addroot
else printroot
fi
}
if [ `grep $user1 /etc/passwd | wc -l` -gt "0" ];
then changepass1 && echo $user1 "already exists , password has been changed."
else createuser1 && echo $user1 "has been created and given root access."
fi
if [ `grep $user2 /etc/passwd | wc -l` -gt "0" ];
then changepass2 && echo $user2 "already exists , password has been changed."
else createuser2 && echo $user2 "has been created and given root access."
fi
if [ `grep $user3 /etc/passwd | wc -l` -gt "0" ];
then changepass3 && echo $user3 "already exists , password has been changed."
else createuser3 && echo $user3 "has been created and given root access."
fi
if [ `grep $user4 /etc/passwd | wc -l` -gt "0" ];
then changepass4 && echo $user4 "already exists , password has been changed."
else createuser4 && echo $user4 "has been created and given root access."
fi
if [ `grep $user5 /etc/passwd | wc -l` -gt "0" ];
then changepass5 && echo $user5 "already exists , password has been changed."
else createuser5 && echo $user5 "has been created and given root access."
fi
exit
You can use logic similar to the following. This assumes each line contains a space separated username/password combo. You can then just act upon $username and $password on each loop cycle:
Code:
$ while read username password; do
> echo "Username is: ${username} Password is: ${password}"
> done < cashman04.txt
Username is: username1 Password is: password1
Username is: username2 Password is: password2
Username is: username3 Password is: password3
$ cat cashman04.txt
username1 password1
username2 password2
username3 password3
EDIT: I think I am starting to get a better grasp of it.. Still not entirely sure where $username and $password are coming from though.
Any chance of some comments of what is going on where? A lot of this is over my head. I have no clue now how the if statement is determining whether to do "then" or "else". Don't see where $username and $password are being set either, lol.
And I'm getting "line 34: [: too many arguments" on the below line:
if [ grep -q "^$username:" /etc/passwd ]
I'm gonna tear it apart for a while and see if I can figure out what is going on...
But thanks so much, I get a little of it, which is helping out immensely.
Quote:
Originally Posted by Chubler_XL
When writing functions use positional parameters instead of hard-coded vars, reads user and password from file:
Not sure why your were using sh -c for the append to /etc/sudoers - changed to standard echo
Code:
#!/bin/bash
createuser(){
useradd -m $1
echo "$1 ALL=(ALL) ALL" >> /etc/sudoers
passwd --stdin $1<<EOF
$2
$2
EOF
}
changepass(){
addroot(){
echo "$1 ALL=(ALL) ALL" >> /etc/sudoers
echo "$1 has been given root access"
}
printroot(){
echo "$1 already has root access"
}
passwd --stdin $1<<EOF
$2
$2
EOF
if [ grep -q "$1 ALL=" /etc/sudoers ]; then
printroot $1
else
addroot $1
fi
}
i=0
while read username password
do
if [ grep -q "^$username:" /etc/passwd ]
then
changepass $username $password
echo "$username already exists , password has been changed."
else
createuser $username $password
echo "$username has been created and given root access."
fi
i=$((i+1))
done < cashman04.txt
Last edited by cashman04; 01-29-2013 at 10:21 PM..
EDIT: username and password come from the while read username password ; do ...... done < input_file statement. In shell if statements run a command and examine it's return code when zero the then part is executed otherwise the else part . ( [ is a shell builtin command used to do standard tests)
Last edited by Chubler_XL; 01-29-2013 at 10:38 PM..
Ok, I am taking this apart bit by bit to understand it. I pretty much get the $username and $password, and how you can use "while read" to get that info, and assign it..
Now though, how are you passing this to $1 and $2? and how does it know to run the command with say user1 and password1, and then user2 and password2 a different time? and over, until end of file?
the shell builtin while continues to run the code between do and done until the read statement returns non-zero (ie end of input file).
When you call a function (like changepass $username $password) $1 $2 $3... $n are populated from the arguments passwd on the function call (in this instance $1 = $username and $2 = $password, and $# is set to 2, indicating 2 arguments were passed).
This makes the changepass function quite useful as you can call it just like other unix commands and pass values directly in like:
Hi,
I know this sounds crazy question.. but I am just curious to know what happens next when I enter username and password and hit enter on a new Unix session (using Putty)? I mean which file gets executed, how the default login shell is determined etc...
regards
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