Shell Programming and Scripting

Folks ,

Trying to create a script / command that kills an application process , but on the ones that are from the current date backwards. So far I have everything working minus the "date" part. Can you help me ?

current command :

Code:

kill -9 `ps -aef | grep app_name | grep -v grep | awk '{print $2}'`

This kills everything under the app_name , however I just want to kill process with the app_name from today's current date back ???? and leave just today's

Please use code tags

Try this

Code:

kill -9 `ps -aef | grep app_name | grep -v grep | awk 'BEGIN {"date +%b%d"|getline dd;}$5!=dd{print $2}'`

regards,
Ahamed

Syntax not correct :


ps -aef | grep naviscore | grep -v grep | awk 'BEGIN {"date +%b%d"|getline dd;}$5!=dd{print $2}'
awk: syntax error near line 1
awk: illegal statement near line 1

Please post the output of "uname -a". If you're on Solaris, use nawk instead of awk.

SunOS nh1a2p32 5.8 Generic_117350-53 sun4u sparc SUNW,Sun-Fire-V440

Yep, that's Solaris. So use nawk rather than awk.

Yep , got that however can not get the part that ahamed101 gave me to work Wonder if there is an easier way to do this ?