TAU_CONTEXT_EVENT(3) TAU Instrumentation API TAU_CONTEXT_EVENT(3)NAME
TAU_CONTEXT_EVENT - Triggers a context event
SYNOPSIS
C/C++:
TAU_CONTEXT_EVENT(TauUserEvent variable, double value);
Fortran:
TAU_CONTEXT_EVENT(integer variable(2), real value);
DESCRIPTION
Triggers a context event. A context event associates the name with the list of routines along the callstack. A context event tracks
information like a user defined event and TAU records the maxima, minima, mean, std. deviation and the number of samples for each context
event. A context event helps distinguish the data supplied by the user based on the location where an event occurs and the sequence of
actions (routine/timer invocations) that preceeded the event. The depth of the the callstack embedded in the context event's name is
specified by the user in the environment variable TAU_CALLPATH_DEPTH. If this variable is not specified, TAU uses a default depth of 2.
EXAMPLE
C/C++ :
int f2(void)
{
static int count = 0;
count ++;
TAU_PROFILE("f2()", "(sleeps 2 sec, calls f3)", TAU_USER);
TAU_REGISTER_CONTEXT_EVENT(event, "Iteration count");
/*
if (count == 2)
TAU_DISABLE_CONTEXT_EVENT(event);
*/
printf("Inside f2: sleeps 2 sec, calls f3
");
TAU_CONTEXT_EVENT(event, 232+count);
sleep(2);
f3();
return 0;
}
Fortran :
integer memevent(2) / 0, 0 /
save memevent
call TAU_REGISTER_CONTEXT_EVENT(memevent, "STORAGEARY mem allocated')
call TAU_CONTEXT_EVENT(memevent, SIZEOF(STORAGEARY)*sizeof(INTEGER))
SEE ALSO TAU_REGISTER_CONTEXT_EVENT(3)
08/31/2005 TAU_CONTEXT_EVENT(3)
Check Out this Related Man Page
XtAppPeekEvent() XtAppPeekEvent()
Name
XtAppPeekEvent - return, but do not remove the event at the head of an application's input queue; block if no events are available.
Synopsis
Boolean XtAppPeekEvent(app_context, event_return)
XtAppContext app_context;
XEvent *event_return;
Inputs
app_context
Specifies the application context.
Outputs
event_return
Returns the event from the head of the queue, if that event is an X event.
Returns
True if the event at the head of the queue is an X event; False if it is a timer event or an alternate input source event.
Description
If there are X events pending on any of the displays in app_context, XtAppPeekEvent() copies the event from the head of the application
event queue into event_return (without removing the event from the queue) and returns True. If there are no events, it flushes the output
buffers of each display and checks again. If there are still no pending X events on any of the displays, but there are timer or alternate
input events ready, XtAppPeekEvent() returns False.
If there are no events of any kind, XtAppPeekEvent() blocks until one occurs, and then if it is an X event, copies the event (without
removing it from the queue) and returns True or returns False otherwise. Note that XtAppPeekEvent() never calls background work procedures
registered with XtAppAddWorkProc() .
Usage
Programs rarely need this much control over the event dispatching mechanism. Most programs use XtAppMainLoop().
If you want to get X events and remove them from the input queue, consider XtAppNextEvent(). This function also dispatches timer and
alternate input events.
If you want to check for input events without blocking, use XtAppPending(). This function returns a value that indicates which types of
events are pending for an application context, or 0 if no events are pending.
See AlsoXtAppMainLoop(1), XtAppNextEvent(1), XtAppPending(1).
Xt - Event Handling XtAppPeekEvent()
I am working within a while loop and i am trying to set a variable that will read out each count of the files. the problem is the count variable i have set up gives me a total and not the individual count of each file. in the data area there is 4 abc.dat and 1 def.dat.
how can i do this???
... (2 Replies)
Hello all, I am currently trying to over-complicate things by doing something similar to the code below:
count=1
for x in $(cat /etc/filename); do
file_$count=$(echo $variable| awk '{print $1}')
count=$(( $count + 1 ))
done
What I expected was different variable names
file_1
file_2
.... (1 Reply)