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Creating a shell script to check filesystem space

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Operating Systems AIX Creating a shell script to check filesystem space
# 8  
Old 06-07-2006
Got it working with:

Code:
#!/bin/ksh
 
used_space=0
mount_point=${1:-"/arch_nb"}
threshold=${2:-65}
 
used_space=`df -k $mount_point | grep -v "^Filesystem" | awk {'print $4'} |sed '
s/%//'`
print "Free Space available under \"$mount_point\" is `expr 100 - $used_space`%.
\n"
 
if [ $used_space -gt $threshold ]
then
   print "Space Utilization on \"$mount_point\" has exceeded the threshhold of $
{threshold}%.\n"
else
   print "Free space on \"$mount_point\" is in normal parameters."
fi

...it turns our that the original statement was returning the header from the "df -k" command in the form of "Iused". This was screwing up the expression in the next line. Thanks to all who helped.
# 9  
Old 06-07-2006
probably best check you've got the right field. I can't remember off hand but df -k might give you free inodes rather than free space hence the Iused header. Try df -I instead and check which field the %free is and adjust your awk statement accordingly.

Smilie
# 10  
Old 06-10-2006
Good idea...thanks.
# 11  
Old 06-18-2006
Quote:
Originally Posted by heprox
When I run the command:

Code:
df -k $mount_point | grep % | awk {'print $5'} | sed 's/%//g'

...assuming I assign the value of "/tmp" to "$mount_point" I get:

Code:
x-4-1-test# df -k /tmp | grep % | awk {'print $5'} | sed 's/%//g'
Iused
774

...its returning a value (although it contains the "Iused" as well? I get the exact same result when I run the command:

Code:
df -k /tmp | grep % | awk '{print $5}' | sed 's/%//g'

...so I dont think the problem is in the qoutes? The problem I think exists in the expression when AIX interprets the "expr" line:

Code:
expr 100 - $used_space`%.\n


you can try

df -k /tmp|grep %|awk 'NR>1{print $3}'|sed 's/%//g'
instead of
df -k /tmp|grep %|awk '{print $5}'|sed 's/%//g'
Last edited by zfengs; 06-18-2006 at 11:15 PM..
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