01-12-2006
Quote:
Originally Posted by Sabari Nath S
ls | xargs -l1 -t -i echo {} `echo {}|awk '{print toupper($0)}'`
`echo {}|wc`
Can anyone tell me the reason why this happens ???
Neither command works for me. You must be testing in a directory with only a few two character filenames if you think the second one works. Create a few longer filenames. The shell sees `echo {} | wc`; so it runs that pipeline and it gets "{} 1 1 3" which it replaces in your command. So then you run:
ls | xargs -l1 -t -i echo {} {} 1 1 3
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ECHO(1) BSD General Commands Manual ECHO(1)
NAME
echo -- write arguments to the standard output
SYNOPSIS
echo [-n] [string ...]
DESCRIPTION
The echo utility writes any specified operands, separated by single blank (' ') characters and followed by a newline ('
') character, to the
standard output.
The following option is available:
-n Do not print the trailing newline character. This may also be achieved by appending 'c' to the end of the string, as is done by iBCS2
compatible systems. Note that this option as well as the effect of 'c' are implementation-defined in IEEE Std 1003.1-2001
(``POSIX.1'') as amended by Cor. 1-2002. Applications aiming for maximum portability are strongly encouraged to use printf(1) to sup-
press the newline character.
Some shells may provide a builtin echo command which is similar or identical to this utility. Most notably, the builtin echo in sh(1) does
not accept the -n option. Consult the builtin(1) manual page.
EXIT STATUS
The echo utility exits 0 on success, and >0 if an error occurs.
SEE ALSO
builtin(1), csh(1), printf(1), sh(1)
STANDARDS
The echo utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'') as amended by Cor. 1-2002.
BSD
April 12, 2003 BSD