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Full Discussion: ls -l | grep $date (failing)
Top Forums Shell Programming and Scripting ls -l | grep $date (failing) Post 79861 by jim mcnamara on Monday 1st of August 2005 03:30:49 PM
Old 08-01-2005
file times are a pain in the butt.

try using the script attached below like this:
Code:
# find files from january 01 2005
for file in `ls -1`
do
      filetime.pl $file | grep -q 20050101
      if [ $? -eq 0 ] ; then
             echo "$file"
      fi
done

Code:
#!/usr/bin/perl
# point the above to the locaction of perl on your system
#^ PROGRAM DESCRIPTION
#^ -------------------
#^ This program prints the modification times of files.
#^ It uses the following format:  inodetime.pl filename
#^ It will accept:  inodetime.pl filename1 filename2 filename3
#^                  inodetime.pl /tmp/file*
#^ The format of the output is: YYYYMMDDhhmmss filename
#^ example:
#^           $ filetime.pl /tmp/t*
#^           19961115105425 /tmp/test.sql 
#^           19970116113616 /tmp/tststat.pl 
#^ 

############################################
# Get the (next) input from the command line 
############################################
while ($curfile = $ARGV[0])
{
   #################################################
   # Do following code block only if $curfile exists
   #################################################
   if (-e $curfile)
   {

      # stat structure into variables

      ($dev,$ino,$mode,$nlink,$uid,$gid,$rdev,$size,
      $atime,$mtime,$ctime,$blksize,$blocks)
      = stat("$curfile");

      # time structure into variables

      local($sec,$min,$hr,$day,$mon,$yr,$wday,@dntcare) = localtime($mtime);
      $yr = ($yr>=70) ? $yr+1900 : $yr+2000;
      $yr="$yr";
      $mon = (++$mon < 10) ? "0$mon" : "$mon";
      $day = ($day < 10) ? "0$day" : "$day";
      $hr  = ($hr < 10) ? "0$hr" : "$hr";
      $min = ($min < 10) ? "0$min" : "$min";
      $sec = ($sec < 10) ? "0$sec" : "$sec";

      # Rearrange in the YYYYMMDDhhmmss format and assign to $dte variable

      $dte = join('',$yr,$mon,$day,$hr,$min,$sec);

      # Print modification date and filename

      print ("$dte\n");
      }

   # Shift to next position in command line
   shift (@ARGV);
}

 

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datetime(3)						     Library Functions Manual						       datetime(3)

NAME
datetime - convert between TAI labels and seconds SYNTAX
#include <datetime.h> void datetime_tai(&dt,t); datetime_sec datetime_untai(&dt); struct datetime dt; datetime_sec t; DESCRIPTION
International Atomic Time, TAI, is the fundamental unit for time measurements. TAI has one label for every second of real time, without complications such as leap seconds. A struct datetime variable, such as dt, stores a TAI label. dt.year is the year number minus 1900; dt.mon is the month number, from 0 (January) through 11 (December); dt.mday is the day of the month, from 1 through 31; dt.hour is the hour, from 0 through 23; dt.min is the minute, from 0 through 59; dt.sec is the second, from 0 through 59; dt.wday is the day of the week, from 0 (Sunday) through 6 (Saturday); dt.yday is the day of the year, from 0 through 365. The datetime library supports more convenient TAI manipulation with the datetime_sec type. A datetime_sec value, such as t, is an integer referring to the tth second after the beginning of 1970 TAI. The first second of 1970 TAI was 0; the next second was 1; the last second of 1969 TAI was -1. The difference between two datetime_sec values is a number of real-time seconds. datetime_tai converts a datetime_sec to a TAI label. datetime_untai reads a TAI label (specifically dt.year, dt.mon, dt.mday, dt.hour, dt.min, and dt.sec) and returns a datetime_sec. SEE ALSO
now(3) datetime(3)
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