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Top Forums Shell Programming and Scripting How to get it's own file name within the same shell script? Post 42370 by Simerian on Tuesday 28th of October 2003 11:14:37 AM
Old 10-28-2003
Belt and braces...

To be sure that you only get the script name, try using:

basename $0

Like so:

LogFile="$(basename $0).log"

This solves the issue of calling the script with a path name attached to the front.
This User Gave Thanks to Simerian For This Post:
 

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basename(1B)					     SunOS/BSD Compatibility Package Commands					      basename(1B)

NAME
basename - display portions of pathnames SYNOPSIS
/usr/ucb/basename string [suffix] DESCRIPTION
The basename utility deletes any prefix ending in `/' and the suffix, if present in string. It directs the result to the standard output, and is normally used inside substitution marks (` `) within shell procedures. The suffix is a string with no special significance attached to any of the characters it contains. EXAMPLES
Example 1: Using the basename command. This shell procedure invoked with the argument /usr/src/bin/cat.c compiles the named file and moves the output to cat in the current direc- tory: example% cc $1 example% mv a.out `basename $1 .c` ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWscpu | +-----------------------------+-----------------------------+ SEE ALSO
sh(1), attributes(5) SunOS 5.10 28 Mar 1995 basename(1B)
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