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Top Forums Shell Programming and Scripting First Time need help on UNIX Command Post 302997534 by RavinderSingh13 on Tuesday 16th of May 2017 01:44:04 AM
Old 05-16-2017
Quote:
Originally Posted by srilu
I just noticed that command above is not written anything on input file ,its idle
---------- Post updated at 04:36 PM ---------- Previous update was at 03:59 PM ----------
Can you help on this.
Hello Srilu,

Rushing while posting your questions will not help us. I think you have never posted like you want the changes inside the Input_file? If this is the case then you may need to take the output of my command into a temp_file and then rename it again as your Input_file like as follows.
Code:
awk '{VAL=$0 !~ /^<code/?(VAL?VAL ORS $0:$0):(VAL?VAL $0:$0)} END{print VAL}'   Input_file > temp_file && mv temp_file  Input_file

I hope this helps you, if your requirement is different then please take sometime and rephrase your questions in detailed manner so that we could try to help you.

Thanks,
R. Singh

Last edited by RavinderSingh13; 05-16-2017 at 02:50 AM..
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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