If you are unsure try a simple interactive longhand example first...
On your "if" line which I assume is line 76 there should be a space in the last condition just before "]":-
Example using OSX 10.7.5 default terminal, bash:-
Note the space missing before the "]"...
EDIT:
I have a sneaking suspicion your entire "if" condition might still give rise to your error on line 80.
Last edited by wisecracker; 09-15-2013 at 12:33 PM..
Reason: Incorrect indent in example...
This User Gave Thanks to wisecracker For This Post:
Hello All,
I have a script that will email out if the email address is specified as parameter 1.
I am using ksh, and then tried the following :
email=$1
Following did not work, I am getting error
test -z $email
test ${email:=" ") -eq " "
test -n $email
test ${?email}
What... (4 Replies)
Hi
I am writing a bash script and would like to check is a variable contains a . or not
ex.
a=102 output ok
a=1.02 output not ok
Many thanks, (3 Replies)
Hi all,
to check that a variable is not empty, I usually do:
if ; then...
or
if ; then...
what if I have a serie of variables and want to do the same test on all of them. How to do this in a single if statement?
thank you (1 Reply)
hi to all,
i want to check the value of a variable that it contains characters.
for example i try the following:
if then .........
i just want to check that in the specific line that is a variable called "passline" has the entry "password". But it can contain also other characters in the... (4 Replies)
I have seen many posts for this sort of problem but I just did not know how to use it for my issue. A number is assigned to a variable and I wanted to check if it is a zero or non zero.
Example of my numbers are below:
000000000000000000000000000000000000000000000000... (8 Replies)
#!/bin/sh
echo "Running Script to capture ORACLE Erros"
# Change Directory to the actual logs path
cd /home/nv8510/lognew
err_var=`grep -in "ORA-" *`
if then
echo "THESE ARE THE ORACLE ERROR OCCURED"
echo "$err_var"
echo... (7 Replies)
I have a script /root/asas with following contents.
#!/bin/bash
ha=`cat /etc/passwd | grep sandra`
if ; then
echo "Sandra is in /etc/passwd"
echo "variable ha is $ha"
else
echo "Sandra is NOT in /etc/passwd"
echo "variable ha is $ha"
fi
What... (3 Replies)
hi,
i want to check whether a a variable contains some value or is empty in a shell script. so if the variable contains some value i want to do some job and if the variable doesnt contain any value then i need to skip that job.
here is a sample script
read_filenames.sh contains
... (5 Replies)
Discussion started by: Little
5 Replies
LEARN ABOUT REDHAT
open
OPEN(1) Linux 1.x OPEN(1)NAME
open - start a program on a new virtual terminal (VT).
SYNOPSIS
open [-c vtnumber] [-s] [-u] [-l] [-v] [--] command command_options
DESCRIPTION
open will find the first available VT, and run on it the given command with the given command options, standard input, output and error are
directed to that terminal. The current search path ($PATH) is used to find the requested command. If no command is specified then the envi-
ronment variable $SHELL is used.
OPTIONS
-c vtnumber
Use the given VT number and not the first available. Note you must have write access to the supplied VT for this to work.
-s Switch to the new VT when starting the command. The VT of the new command will be made the new current VT.
-u Figure out the owner of the current VT, and run login as that user. Suitable to be called by init. Shouldn't be used with -c or -l.
-l Make the command a login shell. A - is prepended to the name of the command to be executed.
-v Be a bit more verbose.
-w wait for command to complete. If -w and -s are used together then open will switch back to the controlling terminal when the command
completes.
-- end of options to open.
NOTE
If open is compiled with a POSIX (Gnu) getopt() and you wish to set options to the command to be run, then you must supply the end of
options -- flag before the command.
EXAMPLES
open can be used to start a shell on the next free VT, by using the command:
open bash
To start the shell as a login shell, use:
open -l bash
To get a long listing you must supply the -- separator:
open -- ls -l
SEE ALSO login(1), doshell(8), switchto(1).
AUTHOR
Jon Tombs <jon@gtex02.us.es or jon@robots.ox.ac.uk>
-w idea from "sam".
19 Jul 1996 V1.4 OPEN(1)