Trying to tar specific files from a directory causes problems when the number of files is too large.
ls ~/logs | wc -l
5928
In the logs directory - I have 5928 files
If I want to include all files with today's date - I run the following command
tar cf ~/archive/LoadLogs_20060302.tar... (8 Replies)
Hi
I executed the code
for file in `ls pdb*.ent`
do
new_name=`echo $file | sed 's/^pdb//;s/.ent/.txt/'`
mv $file $new_name
done
Its giving error at ' ls pdb*.ent' argument list too long
i have around 150000 entries
please help
Thank you (6 Replies)
I have a wrote a script which consits of the below line.. Below of this script I'm getting this error "ksh: /usr/bin/ls: arg list too long"
The line is
log_file_time=`ssh -i $HOME/.ssh/id_rsa -q $i ls -lrt /bp/karthik/test/data/log/$abc*|tail -1|awk '{print $8}'`
And $abc alias is as "p |... (1 Reply)
Hi guys
Following command results in
sed -i 's/#/\\#/g' /home/test/sqlstents*
-bash: /bin/sed: Argument list too long
Please help me solve it.. is there any other way i can do this?.. thanks (4 Replies)
I have a huge set of files (with extension .common) in my directory around 2 million. When I run this script on my Linux with BASH, I get /bin/awk: Argument list too long
awk -F'\t' '
NR == FNR { a=NR }
NR != FNR {
sub(".common", "", FILENAME)
print a, FILENAME, $1
}
'... (1 Reply)
Dear Experts,
I have a list of 10K files in a directory. I am not able to execute any commands lile ls -lrt, awk, sed, mv, etc........
I wanna execute below command and get the output. How can I achieve it?? Pls help.
root# awk -F'|' '$1 == 1' file_20120710* | wc -l
/bin/awk: Argument list... (2 Replies)
Hi,
i am having some trouble with the below command, can some one suggest me the better way to do it.
grep -l 'ReturnCode=1' `find $Log -newer /tmp/Failed.tmp -print | xargs ls -ld | egrep SUB | egrep -ve 'MTP' -ve 'ABC' -ve 'DEF' -ve 'JKL' -ve 'XYZ' | awk '{print $9}'` > $Home1
Its... (2 Replies)
Hi I am using find command --
find "directory1" -type f | xargs -i mv {} "directory2"
to avoid above argument list too long problem.
But, issue i am facing is directory1 is having subdirectories due to this i am facing directory traversal problem as i dont want to traverse subdirectories... (9 Replies)
Hi All,
This question has been asked many times, but my problem is slightly different.
In my shell script i am connecting to oracle database and loading the results to .dat file. This .dat file is later used to create to .xls file Some times the size of .dat file becomes more than 120000... (8 Replies)
Hi Team,
Here's the situation.
I have approximately 300000 to 500000 jpg files in /appl/abcd/work_dir
mv /appl/abcd/work_dir /appl/abcd/process_dir
The above move command will work if the jpg files count is close to 50000 (not sure). If the count is less this mv command holds good. But if... (14 Replies)
Discussion started by: kmanivan82
14 Replies
LEARN ABOUT DEBIAN
yaz-url
YAZ-URL(1) Commands YAZ-URL(1)NAME
yaz-url - YAZ URL fetch utility
SYNOPSIS
yaz-url [-H name:value] [-m method] [-O fname] [-p fname] [-u user/password] [-x proxy] [url...]
DESCRIPTION
yaz-url is utility to get web content. It is very limited in functionality compared to programs such as curl, wget.
The options must be precede the URL given on the command line to take effect.
Fetched HTTP content is written to stdout, unless option -O is given.
OPTIONS -H name:value
Specifies HTTP header content with name and value. This option can be given multiple times (for different names, of course).
-m method
Specifies the HTTP method to be used for the next URL. Default is method "GET". However, option -p sets it to "POST".
-O fname
Sets output filename for HTTP content.
-p fname
Sets a file to be POSTed in the folloing URL.
-u user/password
Specifies a user and a password to be uesd in HTTP basic authentication in the following URL fetch. The user and password must be
separated by a slash (this it is not possible to specify a user with a slash in it).
-x proxy
Specifies a proxy to be used for URL fetch.
SEE ALSO yaz(7)YAZ 4.2.30 04/16/2012 YAZ-URL(1)