Simple awk help Post: 302824775

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I need a hand with this simple script, in Unix i have a variable called portal: $ echo $portal chu0 when i use awk this variable is not recognized. How can i make awk recognize and print the value of this variable, since the output is not shown i.e. awk ' BEGIN {printf("%4s\t%14s\n",...

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when I execute this awk stmt .. awk "/log_directory/ { print $5}" /opt/dba/oraadmin/tools/tmp_purge_op.log it's returning the whole line as .. IRMD118_LISTENER1 parameter "log_directory" set to /opt/oracle/10.2/network/log/ my expected output is : /opt/oracle/10.2/network/log what...

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simple awk help

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Please explain this simple AWK example

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Hi, I have a file such that: 40454,31,48,4,1304.967741935484,1 31708,25,48,4,1268.32,1 20900,64501,671,788,0.3240259840932699,0 20137,51358,834,743,0.3920908135051988,0 I want to replace the 6th column by "ones" if it is 1, and with "zeros" if it is 0. Thanks.

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Hi, this must be a simple but this is my first interaction with shell and awk. following is a log file needed to parse (2 lines separated by a line break for clarity): 2013-07-27 13:32:09,043 - ERROR - PerformanceUtility - Thread-14 - Performance - 9b348407-4f57-4983-a057-a55669821f68 |...

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