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Top Forums Shell Programming and Scripting Run shell script alternate week per month Post 302784389 by krupasindhu18 on Friday 22nd of March 2013 05:40:42 AM
Old 03-22-2013
Run shell script alternate week per month

Hi All,

Requirement :-
I have shell script in kern shell ,have to run alternate week per month
example-today's date is 27 Mar 2013 and my script will run today then for the next time when it will run it should check 1st what was the last run date(27 Mar 2013) if it is matched 15days from current date then run else sent a mail with waning mgs.

i have a AWK command it is checking only within a month
Code:
date +%Y:%m:%d|awk -vFS=":" -vOFS=":" '{$3=$3-3;print}'

suppose i am checking 20days from current date it is give some negative value
ex-2013:03:-8

Please give some advice me so i can move forward.

Thank you All.

Regards,
Krupa

Last edited by vbe; 03-22-2013 at 07:12 AM..
 

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CAL_FROM_JD(3)								 1							    CAL_FROM_JD(3)

cal_from_jd - Converts from Julian Day Count to a supported calendar

SYNOPSIS
array cal_from_jd (int $jd, int $calendar) DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH and CAL_FRENCH. PARAMETERS
o $jd - Julian day as integer o $calendar - Calendar to convert to RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and the date in string form "month/day/year". EXAMPLES
Example #1 cal_from_jd(3) example <?php $today = unixtojd(mktime(0, 0, 0, 8, 16, 2003)); print_r(cal_from_jd($today, CAL_GREGORIAN)); ?> The above example will output: Array ( [date] => 8/16/2003 [month] => 8 [day] => 16 [year] => 2003 [dow] => 6 [abbrevdayname] => Sat [dayname] => Saturday [abbrevmonth] => Aug [monthname] => August ) SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3). PHP Documentation Group CAL_FROM_JD(3)
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