Sponsored Content
Full Discussion: awk gsub with variables
Top Forums UNIX for Dummies Questions & Answers awk gsub with variables Post 302779051 by Don Cragun on Tuesday 12th of March 2013 04:47:39 AM
Old 03-12-2013
If all you want to do is add a 0 after input character number 64 on lines that don't contain the string TLR, you don't need cat, cut, or gsub(); you just need awk's substr() and print functions.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

use var in gsub of awk

Hi all, This problem has cost me half a day, and i still do not know how to do. Any help will be appreciated. Thanks advance. I want to use a variable as the first parameters of gsub function of awk. Example: { ... arri]=gsub(i,tolower(i),$1) (which should be ambraced by //) ... } (1 Reply)
Discussion started by: summer_cherry
1 Replies

2. Shell Programming and Scripting

Help with AWK and gsub

Hello, I have a variable that displays the following results from a JVM.... 1602100K->1578435K I would like to collect the value of 1578435 which is the value after a garbage collection. I've tried the following command but it looks like I can't get the > to work. Any suggestions as... (4 Replies)
Discussion started by: npolite
4 Replies

3. Shell Programming and Scripting

awk gsub

Hi all I want to do a simple substitution in awk but I am getting unexpected output. My function accepts a time and then prints out a validation message if the time is valid. However some times may include a : and i want to strip this out if it exists before i get to the validation. I have shown... (4 Replies)
Discussion started by: pxy2d1
4 Replies

4. Shell Programming and Scripting

Awk Gsub Query

Hi, Can some one please explain the following line please throw some light on the ones marked in red awk '{print $9}' ${FTP_LOG} | awk -v start=${START_DATE} 'BEGIN { FS = "." } { old_line1=$0; gsub(/\-/,""); if ( $3 >= start ) print old_line1 }' | awk -v end=${END_DATE} 'BEGIN { FS="." } {... (3 Replies)
Discussion started by: crosairs
3 Replies

5. Shell Programming and Scripting

Awk gsub error.

I want to replace comma with space and "*646#" with space. I am using the following code: nawk -F"|" '{gsub(","," ",$3); gsub(/\*646\#/"," ",$3);print}' OFS="|" file I am getting following error: Help is appreciated (5 Replies)
Discussion started by: pinnacle
5 Replies

6. Shell Programming and Scripting

Help with awk and gsub using C shell

Being new to awk, I am still running into little stupid things. For this issues I am trying to search for all occurrences of a string in a file and replace all of those occurrences with a replacement string. I tried doing awk '{gsub("|750101|", "|000000|", $0)}' infile > outfile Unix... (3 Replies)
Discussion started by: jclanc8
3 Replies

7. Shell Programming and Scripting

awk gsub with variables?

Hey, I would like to replace a string by a new one. Teh problem is that both strings should be variables to be flexible, because I am having a lot of files (with the same structure, but in different folders) for i in daysim_* do cd $i/5/ folder=`pwd |awk '{print $1}'` awk '{ if... (3 Replies)
Discussion started by: ergy1983
3 Replies

8. Shell Programming and Scripting

Awk; gsub in fields 3 and 4

I want to transform a log file into input for a database. Here's the log file: Tue Aug 4 20:17:01 PDT 2009 Wireless users: 339 Daily Average: 48.4285 = Tue Aug 11 20:17:01 PDT 2009 Wireless users: 295 Daily Average: 42.1428 = Tue Aug 18 20:17:01 PDT 2009 Wireless users: 294 Daily... (6 Replies)
Discussion started by: Bubnoff
6 Replies

9. Shell Programming and Scripting

awk gsub

Hi, I want to print the first column with original value and without any double quotes The output should look like <original column>|<column without quotes> $ cat a.txt "20121023","19301229712","100397" "20121023","19361629712","100778" "20121030A","19361630412","100838"... (3 Replies)
Discussion started by: ysrini
3 Replies

10. Shell Programming and Scripting

Gsub function in awk

Hello, I had some difficulty to understand the gsub function and maybe the regex in this script to remove all the punctuations: awk 'gsub(//, " ", $0)' text.txtFile text.txt: This is a test for gsub I typed this random text file which contains punctuation like ,.;!'"?/\ etc. The script... (6 Replies)
Discussion started by: yifangt
6 Replies
cat(1)							      General Commands Manual							    cat(1)

Name
       cat - concatenate and print data

Syntax
       cat [ -b ] [ -e ] [ -n ] [ -s ] [ -t ] [ -u ] [ -v ] file...

Description
       The  command reads each file in sequence and displays it on the standard output.  Therefore, to display the file on the standard output you
       type:
       cat file
       To concatenate two files and place the result on the third you type:
       cat file1 file2 > file3
       To concatenate two files and append them to a third you type:
       cat file1 file2 >> file3
       If no input file is given, or if a minus sign (-) is encountered as an argument, reads from the standard input file.  Output is buffered in
       1024-byte blocks unless the standard output is a terminal, in which case it is line buffered.  The utility supports the processing of 8-bit
       characters.

Options
       -b   Ignores blank lines and precedes each output line with its line number.

       -e   Displays a dollar sign ($) at the end of each output line.

       -n   Precedes all output lines (including blank lines) with line numbers.

       -s   Squeezes adjacent blank lines from output and single spaces output.

       -t   Displays non-printing characters (including tabs) in output.  In addition to those representations used with the -v  option,  all  tab
	    characters are displayed as ^I.

       -u   Unbuffers output.

       -v   Displays  non-printing  characters (excluding tabs and newline) as the ^x.	If the character is in the range octal 0177 to octal 0241,
	    it is displayed as M-x. The delete character (octal 0177) displays as ^?.  For example, is displayed as ^X.

See Also
       cp(1), ex(1), more(1), pr(1), tail(1)

																	    cat(1)
All times are GMT -4. The time now is 09:35 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy