I want to do a grep with AND condition.
I have three files.
file1.txt
========
UNIX
......
WINDOWS
........
ORACLE
file2.txt
========
UNIX
.......
WINDOWS
...and many such files in a directory (6 Replies)
1. The problem statement, all variables and given/known data:
I have to grep a data file called datebook.txt. The last information in each line is a salary. I have to grep all the lines which precede those lines with 6 figure salaries. I can't SID it, or use Perl. It has to be grep (or egrep or... (3 Replies)
hi i need help with below code.
if ]
then
log "Exiting the script as ID= NULL"
log "Please run script first."
fi
i am calling grep inside this but its not running any ideas why ??
input file is like this --
Msg 102, Level 20, State 1:
Server... (4 Replies)
Hi,
In this code can able to match the pattern without case sensitive. Is that possible?
if u knw plz help me...
code:
echo "Enter name to search"
read n
if ;
echo "name found"
else
echo "Not Found"
fi (8 Replies)
I have below files under dir_a and dir_b and i want to sort out number of dir_a and dir_b files seperately and if i do the grep it should retrun 2 files in dir_a and 1 file in dir_b.
/dir_a/12345678
/dir_a/87654321
/dir_a/dir_b/12345687
But i am getting cat file|grep dir_a|wc -l
3... (6 Replies)
file input
aaaa,52C
aaaa,50C
bbbb,50C
bbbb,58C
aaaa,52C
bbbb,50C
aaaa,30C
bbbb,58C
cccc,60C
i want to print uniq lines with its max value of column2
expected output
aaaa,52C
bbbb,58C
cccc,60C
tks (4 Replies)
hi all,
i have an xml what i have to do is to search for the source id(s1) and if it matches with that in xml then extract the file mask from the name of the file i.e if the file name is
idr_%YYYY%%MM%%DD%_%N%.idr then , i want the part after first %
and before last % ie in this case
... (5 Replies)
I have file input
AAAA_XX_Start> rlong . 0W
130526-11:36:13 10.128.13.226 9.0j RBS_NODE_MODEL_N_1_50 stopfile=/tmp/13019
..
=================================================================================================================
MO ... (2 Replies)
Discussion started by: radius
2 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)