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Top Forums UNIX for Advanced & Expert Users [SOLVED] Code does not run when assigned to a variable Post 302738193 by newbie2010 on Friday 30th of November 2012 01:54:36 PM
Old 11-30-2012
This is the bash root shell. I have tried to just echo an array, and it completes successfully but then still gives the same input as before. I am also not able to make the for loop work, see below. This is probably because I do not have much experience with arrays. But the basic echo array returns the /vol/root without any subdirectories. Maybe I am not making the loop for the iteration correctly.

Basic echo array:

Code:
declare -a array=( $(su nbadmin -c "ssh -t servery /usr/openv/netbackup/bin/bplist -C servery -t 19 -l -R -s 11/01/20
12 -e 11/01/2012 -e 11/01/2012 /vol/root/") )
echo ${array[$i]}

this gives errors:
Code:
declare -a array=( $(su nbadmin -c "ssh -t servery /usr/openv/netbackup/bin/bplist -C servery -t 19 -l -R -s 11/01/2012 -e 11/0
12 -e 11/01/2012 -e 11/01/2012 /vol/root/") )
for (( i = 0; i < ${#array[@]}; i++ ))
do
 echo ${array[$i]}
done

Errors:
+ declare -a 'array=( drwxr-xr-x root root 4096 May 25 2012 /vol/root/ )'
testing_1130: line 2: syntax error near unexpected token `(('
testing_1130: line 2: `for (( i = 0; i < ${#array[@]}; i++ ))'

Again, any help you gurus have is always appreciated.

Last edited by joeyg; 11-30-2012 at 03:20 PM.. Reason: Please wrap data and sripts with CodeTags
 

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MIN(3)									 1								    MIN(3)

min - Find lowest value

SYNOPSIS
mixed min (array $values) DESCRIPTION
mixed min (mixed $value1, mixed $value2, [mixed $...]) If the first and only parameter is an array, min(3) returns the lowest value in that array. If at least two parameters are provided, min(3) returns the smallest of these values. Note Values of different types will be compared using the standard comparison rules. For instance, a non-numeric string will be com- pared to an integer as though it were 0, but multiple string values will be compared alphanumerically. The actual value returned will be of the original type with no conversion applied. PARAMETERS
o $values - An array containing the values. o $value1 - Any comparable value. o $value2 - Any comparable value. o $... - Any comparable value. RETURN VALUES
min(3) returns the parameter value considered "lowest" according to standard comparisons. If multiple values of different types evaluate as equal (e.g. 0 and 'abc') the first provided to the function will be returned. EXAMPLES
Example #1 Example uses of min(3) <?php echo min(2, 3, 1, 6, 7); // 1 echo min(array(2, 4, 5)); // 2 // The string 'hello' when compared to an int is treated as 0 // Since the two values are equal, the order they are provided determines the result echo min(0, 'hello'); // 0 echo min('hello', 0); // hello // Here we are comparing -1 < 0, so -1 is the lowest value echo min('hello', -1); // -1 // With multiple arrays of different lengths, min returns the shortest $val = min(array(2, 2, 2), array(1, 1, 1, 1)); // array(2, 2, 2) // Multiple arrays of the same length are compared from left to right // so in our example: 2 == 2, but 4 < 5 $val = min(array(2, 4, 8), array(2, 5, 1)); // array(2, 4, 8) // If both an array and non-array are given, the array is never returned // as comparisons treat arrays as greater than any other value $val = min('string', array(2, 5, 7), 42); // string // If one argument is NULL or a boolean, it will be compared against // other values using the rule FALSE < TRUE regardless of the other types involved // In the below examples, both -10 and 10 are treated as TRUE in the comparison $val = min(-10, FALSE, 10); // FALSE $val = min(-10, NULL, 10); // NULL // 0, on the other hand, is treated as FALSE, so is "lower than" TRUE $val = min(0, TRUE); // 0 ?> SEE ALSO
max(3), count(3). PHP Documentation Group MIN(3)
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