Solaris 10 doesn't seem to like me a lot. I am trying to run a simple script to accept date and return epoch of that date:
#!/usr/bin/perl -w
use strict;
use Time::ParseDate;
my($date1)="Mon Mar 27 05:54:08 CDT 2009";
chomp $date1;
#Convert to seconds since start of epoch
my $time1 =... (3 Replies)
Hello
I have a the creation date of a file stored in a variable in the following format:
Wed May 06 10:14:58 2009Is there a way I can echo the variable and display it in epoch time?
I've done a lot of searching on this topic, but haven't managed to get a solution. I'm on Solaris 10.
... (2 Replies)
System: HP-UX
Kornshell
Perl is installed, but not POSIX
Hello,
I am calculating a future date/time. To do this I take the system date in epoch format and add to it. I now need to take the new epoch date and convert it to MMDDYYHHmm format.
Any help with this is greatly appreciated. (4 Replies)
Hello
I have log file from solaris system which has date field converted by Java application using System.currentTimeMillis() function, example is 1280943608380 which equivalent to GMT: Wed, 04 Aug 2010 17:40:08 GMT.
Now I need a function in shell script which will convert 1280943608380... (3 Replies)
Looking for some help and usually when I do a search this site comes up. Hopefully someone can give me a little direction as to how to use one of these two commands to achieve what I'm trying to do.
What am I trying to do?
I need to take the time value in epoch format returned from the... (5 Replies)
I am not able to pass date stored in a variable as an argument to date command. I get current date value for from_date and to_date
#!/usr/bin/ksh
set -x
for s in server ; do
ssh -T $s <<-EOF
from_date="12-Jan-2015 12:02:09"
to_date="24-Jan-2015 13:02:09"
echo \$from_date
echo... (7 Replies)
Hi All,
I have scenario where i have to compare two dates.
I thought of converting them to epoch seconds and do a numeric comparison.
This works fine on Linux systems.
$ date -d '2015/12/31' +%s
1451538000
$ date +%s
1449159121
But we don't have -d option in HPUX.
What would be... (5 Replies)
Team,
I am working on a shell script and i am extracting a date string in "SunOS server" with below format.
Mon Jan 21 04:13:48 EST 2021
Can you please assist me the best way to convert the extracted string to epoch time like "date +%s" in Linux.
Thanks in advance (1 Reply)
Hello Team,
I am stuck in getting the required output in the following case. Please help.
My input file is
aa|08/01/2016
bb|08/15/2016
I wish to convert the file into
aa|epoch time
bb|epoch time
I am using following code: (3 Replies)
Discussion started by: angshuman
3 Replies
LEARN ABOUT PHP
datetime.modify
DATETIME.MODIFY(3) 1 DATETIME.MODIFY(3)DateTime::modify - Alters the timestamp
Object oriented style
SYNOPSIS
public DateTime DateTime::modify (string $modify)
DESCRIPTION
Procedural style
DateTime date_modify (DateTime $object, string $modify)
Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3).
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $modify
-A date/time string. Valid formats are explained in Date and Time Formats.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.6 | |
| | |
| | Absolute date/time statements now take effect. |
| | Previously, only relative parts were used. |
| | |
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.modify(3) example
Object oriented style
<?php
$date = new DateTime('2006-12-12');
$date->modify('+1 day');
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2006-12-12');
date_modify($date, '+1 day');
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2006-12-13
Example #2
Beware when adding or subtracting months
<?php
$date = new DateTime('2000-12-31');
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
SEE ALSO strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes-
tamp(3).
PHP Documentation Group DATETIME.MODIFY(3)