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Top Forums Shell Programming and Scripting How to get last directory path in script Post 302669183 by tukuyomi on Tuesday 10th of July 2012 02:26:33 PM
Old 07-10-2012
Another way:
Code:
~/unix.com$ d='/root/logs/testing/today/'; echo ${d%/*/}
/root/logs/testing

This User Gave Thanks to tukuyomi For This Post:
 

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GETBUILDLOG(1)						      General Commands Manual						    GETBUILDLOG(1)

NAME
getbuildlog - download build logs from Debian auto-builders SYNOPSIS
getbuildlog package [version-pattern] [architecture-pattern] DESCRIPTION
getbuildlog downloads build logs of package from Debian auto-builders. It downloads build logs of all versions and for all architectures if version-pattern and architecture-pattern are not specified or empty, otherwise only build logs whose versions match version-pattern and build logs whose architectures match architecture-pattern will be downloaded. The version and architecture patterns are interpreted as extended regular expressions as described in grep(1). If version-pattern is "last" then only the logs for the most recent version of package found on buildd.debian.org will be downloaded. If version-pattern is "last-all" then the logs for the most recent version found on each build log index will be downloaded. OPTIONS
-h, --help Show usage information and examples. -V, --version Show version and copyright information. EXAMPLES
getbuildlog hello 2.2-1 amd64 Download amd64 build log for hello version 2.2-1. getbuildlog glibc "" mips.* Download mips(el) build logs of all glibc versions. getbuildlog wesnoth .*bpo.* Download all build logs of backported wesnoth versions. AUTHOR
Written by Frank S. Thomas <fst@debian.org>. DEBIAN
Debian Utilities GETBUILDLOG(1)
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